We have been given that on the day of his 18th birthday Harry decided to start saving money regularly
. Starting on that day, he could save 30.00 on the same date every month. We are asked to find the amount saved by the day before Harry's 60th birthday.
First of all, we will find years from 18 years to 60 years.
We know that 1 year equals 12 months.
To find total amount saved, we will multiply 504 months by amount saved per month.
Therefore, Harry would have saved 
by the day before his 60th birthday.
I'm pretty sure the answer is
<span>B. y = 6x
C. y = x2 - 2</span>
420 x 4 = 1,680. $1,624 - $1,680 = - $56. $600 x 2 = 1,200 + 1000 = 2,200. This minus the $56 he overdrew = an end of month balance of $2,144.
Answer:
Step-by-step explanation:
Alternate forms:
x^2 + y (y + 4) = 5
x^2 + y^2 + 4 y - 5 = 0
Solutions:
y = -sqrt(9 - x^2) - 2
y = sqrt(9 - x^2) - 2
Integer solutions:
x = ± 3, y = -2
x = 0, y = -5
x = 0, y = 1
Implicit derivatives:
(dx(y))/(dy) = -(2 + y)/x
(dy(x))/(dx) = -x/(2 + y)
Answer:
x=6 y=-3
Step-by-step explanation:
