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3 years ago

44% of 25 is what number??

Mathematics

2 answers:

saul85 [17]3 years ago

5 0

We have an equation: ?/25= 44/100

Cross multiply:
100*?= 25*44
⇒ ?= 25*44/100= 11

The final answer is 11~

babunello [35]3 years ago

4 0

44% of 25 is 11
you multiply .44 to 25 to get 11

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Carina begins to solve the equation -4 - 2/3x = -6 by adding 4 to both sides. Which statements regarding the rest of the solving

Andru [333]

Answer:

A.) After adding 4 to both sides, the equation is $-\frac{2}{3}x=-2$

C.) The equation can be solved for x using exactly one more step by multiplying both sides by $-\frac{3}{2}$

D.) The equation can be solved for x using exactly one more step by dividing both sides by $-\frac{2}{3}$

Step-by-step explanation:

The correct questions is as follows:

Carina begins to solve the equation -4-2/3x=-6 by adding 4 to both sides. Which statements regarding the rest of the solving process could be true? Check all that apply.

A.) After adding 4 to both sides, the equation is -2/3x=-2.

B.) After adding 4 to both sides, the equation is -2/3x=-10 .

C.) The equation can be solved for x using exactly one more step by multiplying both sides by -3/2.

D.) The equation can be solved for x using exactly one more step by dividing both sides by -2/3.

E.) The equation can be solved for x using exactly one more step by multiplying both sides by -2/3.

Given equation:

$-4-\frac{2}{3}x=-6$

To show the steps we will carry out in order to solve for $x$

Solution:

Solving for $x$

Step 1:

Adding both sides by 4

$4-4-\frac{2}{3}x=-6+4$

Thus, we get:

$-\frac{2}{3}x=-2$

Thus statement A is correct.

Step 2:

Multiplying both sides by $-\frac{3}{2}$

$-\frac{3}{2}\times -\frac{2}{3}x=-2\times -\frac{3}{2}$

Thus, we get:

$x=3$ [Two negatives multiply to give a positive]

This proves that statement C is correct.

Or Step 2:

Dividing both sides by $-\frac{2}{3}$

$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{-2}{-\frac{2}{3}}$

Thus, we get:

$x=-2\times -\frac{3}{2}$ [On dividing with a fractional divisor, we take reciprocal and multiply it with the dividend.]

$x=3$ [Two negatives multiply to give a positive]

This prove that statement D is correct.

5 0

3 years ago

What's the answer to number 7

Law Incorporation [45]

Ginny is correct. Five quarters makes it $1.25 plus three dimes which is $.30 makes it $1.55

8 0

3 years ago

Read 2 more answers

Plz help I have no idea how to answer it

saveliy_v [14]

5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0 and x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0 then p = -4m and q = 3m²

3p² = 3(-4m)² 16q = 16(3m²)

= 3(16m²) = 48m²

= 48m²

3p² = 48m² = 16q ⇒ 3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

Bigger non-shaded Δ: L = 12-x, w = 10 ⇒ $A = \dfrac{10(12-x)}{2}$
Smaller non-shaded Δ: L = x, w = x ⇒ $A=\dfrac{x(x)}{2}$

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

$\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}$

Area of ΔBEF:

$\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18$

5 0

3 years ago

Mr. Smith wants to build a rectangular gate with a diagonal as support. If the width and height are 4 ft and 3 ft respectively,

frutty [35]

Answer:

5 feet :)

Step-by-step explanation:

6 0

3 years ago

C. Find a parametrization for the line segment with endpoints (-1, 3) and (3, -2).

wel

Answer:

x(t) = -1 + 4t

y (t) = 3 - 5t

Step-by-step explanation:

The end points of the line segment are (-1, 3) and (3, -2).

Let a = (-1,3) and b = (3,-2)

Now, find the value of (b-a)

(b-a) = ((3+1), (-2-3))

b-a = (4, -5)

Therefore, the parametrization of the given line segment is

r(t) = a + (b-a)t

r(t) = (-1,3) +(4,-5)t

r(t) = (-1+4t, 3-5t)

We can rewrite this as

x(t) = -1 + 4t

y (t) = 3 - 5t

3 0

3 years ago