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2 years ago

I need the following solutions to the following equations.

Mathematics

1 answer:

Alja [10]2 years ago

3 0

Answer:

x = 6

y = -9

x = -25

Step-by-step explanation:

1st Equation

Step 1: Write out equation

3(4x - 3) - 19 = 8x - 4

Step 2: Solve

12x - 9 - 19 = 8x - 4

12x - 28 = 8x - 4

4x - 28 = -4

4x = 24

x = 6

2nd Equation

Step 1: Write out equation

-6y + 14 = 32 - 4y

Step 2: Solve

-2y + 14 = 32

-2y = 18

y = -9

3rd Equation

Step 1: Write out equation

-28 + 5 - 3x = 2 - 2x

Step 2: Solve

-23 - 3x = 2 - 2x

-23 = 2 + x

-25 = x

x = -25

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2 years ago

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2 years ago

What does 9/10-13/18 equal as an improper fraction 100 points

Liono4ka [1.6K]

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$\huge \frac{8}{45}$

Step-by-step explanation:

$\frac{9}{10} - \frac{13}{18} \\ \\ = \frac{9 \times 9}{10 \times 9} - \frac{13 \times 5}{18 \times 5} \\ \\ = \frac{81}{90} - \frac{65}{90} \\ \\ = \frac{81 - 65}{90}\\ \\ = \frac{16}{90} \\ \\ = \frac{8}{45} \\$

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3 years ago

It is commonly assumed that babies are equally likely to come as either a boy or a girl. This is not true. Actually, about 51.3%

Brums [2.3K]

Answer: 0.263169

Step-by-step explanation:

Since for every child there is two outcomes (either a boy or a girl), so it is a binomial distribution.

Let x = Number of boys

Given: probability that a child is a boy: p= 0.513

Binomial distribution formula : $P(X=x)=^nC_xp^x(1-p)^{n-x}$

Now, the probability that both children are boys= $P(X=2)=^2C_2(0.513)^2(1-0.513)^0$

$=(1)(0.513)^2(1)\\\\=0.263169$

The chance both children are boys = 0.263169

3 0

2 years ago