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KatRina [158]
3 years ago
15

The temperature on a particular day started at –13°F. It rose steadily by 3° each hour. The function y = –13 + 3x models the tem

perature, where x is the number of hours and y is the temperature. Graph the equation.
Mathematics
1 answer:
Karolina [17]3 years ago
6 0
Graph your y-intercept (-13) first then graph according to slope. Remember ride over run so you would go up 3 and over 1 to find your next point
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A truck enters a highway at 60 mph. A car enters the highway at the same place 11 minutes later and drives 74 mph in the same di
Crank

Answer:

Since speed is given in terms of "hours" we must convert 9 minutes to hours:

9 minutes = 9/60 hours = 3/20 hours

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Let x = time (hours) it takes car to pass the truck

then

60(x + 3/20) = 69x

multiplying both sides by 20:

60(20x + 3) = 1380x

1200x + 180 = 1380x

180 = 180x

1 hour = x

Step-by-step explanation:

5 0
3 years ago
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Given the two relations, which one is a function and why is the other one not a function
Reil [10]

Answer:

The other one (number2) is not a function, because if you plot those points in a graph and use the line rule it shows that more than one point is aligned in that line.

Step-by-step explanation:

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3 years ago
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PLZ HELP!!!!!!! A sequence is defined by the recursive function f(n + 1) = f(n) – 2.
tensa zangetsu [6.8K]

Answer:

f(n + 1) = f(n) - 2 \\ n = 1 -  -  -  - f(1 + 1) =f(1) - 2 \:  \:  \:  -  -   - >   \:  \: f(2) = 10 - 2 = 8 \\ f(2) = 8 \\ n = 2 -  -  -  - f(2 + 1) = f(2) - 2 \:  \:  \:  -  -  -  >  \:  \:  \: f(3) = 8 - 2 = 6 \\ so \: f(3) = 6 \\ and \: we \: are \: done.

3 0
3 years ago
Which is the equation of a line that is perpendicular to the line represented represented by y = 3/4x - 1/2 ?
expeople1 [14]
It will be
.. y = -4/3x +c . . . . . for some value of c

_____
The slope of the perpendicular line will be the negative reciprocal of the slope of the given line, which is 3/4.
6 0
4 years ago
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An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 37 type K batteries and a sample of 58
inna [77]

Answer:

Step-by-step explanation:

Hello!

You want to test two samples of batteries to see is the mean voltage of these battery types are different.

<u>Sample 1 </u>(type K)

n₁= 37

sample mean x₁[bar]= 8.54

standard deviation S₁= 0.225

<u>Sample 2 </u>(Type Q)

n₂= 58

sample mean x₂[bar]= 8.69

standard deviation S₂= 0.725

1. The test hypothesis are:

H₀: μ₁ = μ₂

H₁: μ₁ ≠ μ₂

2. I'll apply the Central Limit Theorem and approximate the distribution of the sample means to normal so that I can use an approximate Z statistic for this test.

Z:<u> (x₁[bar] - x₂[bar]) - (μ₁ - μ₂)</u> ≈ N(0;1)

        √ (S₁²/n₁) + (S₂²/n₂)

Z_{H0}= (8.54 - 8.69) / [√ (0.225²/37) + (0.725²/58)]

Z_{H0}= -1.468 ≅ -1.47

3. This is a two tailed test, so you'll have two critical values

Z_{\alpha/2} = Z_{0.025} = - 1.96

Z_{1 - \alpha/2} = Z_{0.975} = 1.96

You'll reject the null hypothesis if Z_{H0} ≤ -1.96 or if Z_{H0} ≥ 1.96

You'll not reject the null hypothesis if -1.96 < Z_{H0} < 1.96

4.

Since the value Z_{H0} = -1.47 is in the acceptance region, the decision is to not reject the null hypothesis.

I hope it helps!

5 0
4 years ago
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