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2 years ago

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The temperature on a particular day started at –13°F. It rose steadily by 3° each hour. The function y = –13 + 3x models the tem

perature, where x is the number of hours and y is the temperature. Graph the equation.

1 answer:

Karolina [17]2 years ago

6 0

Graph your y-intercept (-13) first then graph according to slope. Remember ride over run so you would go up 3 and over 1 to find your next point

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MUST EXPLAIN NOT A STRAIGHT UP ONE ANSWER OR REPORTED

dmitriy555 [2]

Answer:

Step-by-step explanation:

170=40x+50

170=40x+50 subtract 50

120=40x divide by 40

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2 years ago

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Solve for x. 45(15x+20)−7x=56(12x−24)+6

Nady [450]

Answer:

The value of the equation for x is $x=\frac{1119}{2}$ or 559.5.

Step-by-step explanation:

Consider the provided equation.

$45(15x+20)-7x=56(12x-24)+6$

We need to solve the equation for x.

Use the distributive property: $a(b+c)=ab+ac$

$45(15x+20)-7x=56(12x-24)+6$

$675x+900-7x=672x-1344+6$

Add the like terms.

$668x+900=672x-1338$

Isolate the variable as shown:

$672x-668x=900+1338$

$4x=2238$

$x=\frac{2238}{4}$

$x=\frac{1119}{2}$

Hence, the value of the equation for x is $x=\frac{1119}{2}$ or 559.5.

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3 years ago

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SOLVE THE EQUATION FOR Y

max2010maxim [7]

$(4)\ -6x + y = 11\ \ \ \Rightarrow\ \ \ y=6x+11\\\\(5)\ \ 8x + 2y = 10\ \ \ \Rightarrow\ \ \ 2y=-8x+10\ \ \ \Rightarrow\ \ \ y=-4x+5\\\\(6)\ \ 6x - 3y = -9\ \ \ \Rightarrow\ \ \ -3y=-6x-9\ \ \ \Rightarrow\ \ \ y=2x+3\\\\(7)\ \ -4x + 2y = 16\ \ \ \Rightarrow\ \ \ 2y=4x+16\ \ \ \Rightarrow\ \ \ y=2x+8\\\\
(8)\ \ 10x - 5y = 25\ \ \ \Rightarrow\ \ \ -5y=-10x+25\ \ \ \Rightarrow\ \ \ y=2x-5\\\\(9)\ \ 3x + 2y = -8\ \ \ \Rightarrow\ \ \ 2y=-3x-8\ \ \ \Rightarrow\ \ \ y=-1.5x-4
$

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3 years ago

Factor the expression.

tiny-mole [99]

B. (k+10f)(k-5f) you can tell in 2 ways. 1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D. Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.

The second way is to FOIL them out. When you check B you get $k^{2} -5kf+10kf- 50f^{2}$ combine your like terms and you have your original expression of $k^{2} +5kf-50 f^{2}$

Hope that helps

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3 years ago