Answer:
∠ADB = γ/2 +90°
Step-by-step explanation:
Here's one way to show the measure of ∠ADB.
∠ADB = 180° - (α + β) . . . . . sum of angles in ΔABD
∠ADB + (2α +β) + γ + (2β +α) = 360° . . . . . sum of angles in DXCY
Substituting for (α + β) in the second equation, we get ...
∠ADB + 3(180° - ∠ADB) + γ = 360°
180° + γ = 2(∠ADB) . . . . . . add 2(∠ADB)-360°
∠ADB = γ/2 + 90° . . . . . . . divide by 2
_____
To find angles CXD and CYD, we observe that these are exterior angles to triangles AXB and AYB, respectively. As such, those angles are equal to the sum of the remote interior angles, taking into account that AY and BX are angle bisectors.
Cards = x
Bouquets = y
They spend 2 on each card so 2x and 3.50 for each bouquet so 3.50y add those together to get the total they can spend 2x + 3.50y = 360
Then add the sales together: 6x + 8y = 900
Answer: D. 2x + 3.50y = 360; 6x + 8y = 900
-8,-5, 6, 11, 16: reasoning if the number is a higher negative it makes it less
Answer:
9
Step-by-step explanation:
The absolute value of -3 is |-3|, which in turn is 3. Thus we have
3(3), or 9. The fourth answer choice is the correct one.
x = total amount of students in 8th Grade.
we know only one-thrid of the class went, so (1/3)x or x/3 went.
we also know 5 coaches went too, and that the total amount of that is 41.
now, to verify, well, what do you get for (108/3) + 5?
