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gladu [14]
4 years ago
6

Six less than 2 times y is 34

Mathematics
1 answer:
Zina [86]4 years ago
7 0

14 because 34-6=28 and 28 divided by 2 is 14. Idk if it’s right tho

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Mrs. Murphy bought 4 packages of paper lanterns, 12 bags of balloons, 11

garlands and 4 banners

Step-by-step explanation:

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2 years ago
Simplify 6 - (-2) - 3(-5)
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So the first thing we need to do is multiply 3*-5, since order of operations dictates it (PEMDAS)

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The circle below is centered at the origin and has a radius of 5. What is its
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Convert the following unsigned binary number to unsigned decimal.<br><br> 110011.101
tangare [24]

Answer:

51.625

Step-by-step explanation:

Given a unsigned binary number, to calculate the unsigned decimal:

first, starting at dot, you list the positive powers of 2 from right to left beginning in 2^{0}  that is equal to “1”.  Increase by one the exponent in every power until you complete the total quantity of digits from the unsigned binary number. In this case, since dot to the left, the binary number has six digits (110011). That is to say that you get the followings powers: 2^{5}  2^{4}  2^{3} 2^{2}  2^{1}  2^{0}.

Second, do the same from dot to the right but this time, you list the negative powers of 2 from left to right beginning in 2^{-1} that is equal \frac{1}{2} = 0.5. so you get:    2^{-1}  2^{-2}  2^{-3}

Now, join two parts and you get:

2^{5}      2^{4}     2^{3}      2^{2}      2^{1}       2^{0}    2^{-1}      2^{-2}      2^{-3}

1        1       0       0       1       1.        1        0        1

Then, you write the equivalent of each of the power below from corresponding binary digit, like that:

2^{5}      2^{4}     2^{3}      2^{2}      2^{1}       2^{0}    2^{-1}      2^{-2}      2^{-3}

1        1       0       0       1       1.        1        0        1

|         |        |         |        |        |         |         |         |  

32    16      8       4       2       1       0.5   0.25   0.125  

Finally, you write under the line the equivalent of each power that corresponding to “1” and write “0” under the line, the one that corresponding to “0”, and you sum each one of finals values. Like that:

2^{5}      2^{4}     2^{3}      2^{2}      2^{1}       2^{0}    2^{-1}      2^{-2}      2^{-3}

1        1       0       0       1       1.        1        0        1

|         |        |         |        |        |         |         |         |  

32    16      8       4       2       1       0.5   0.25   0.125  

_______________________________________  

32    16      0       0       2       1       0.5     0      0.125  

32 + 16 + 0 + 0 + 2 + 1 + 0.5+ 0 + 0.125 = 51.625

So that the equivalent from unsigned binary number 110011.101 to unsigned decimal is 51.625

5 0
4 years ago
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