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3 years ago

There is a bag filled with 6 blue and 5 red marbles.

Mathematics

1 answer:

kherson [118]3 years ago

5 0

Answer:

60/121

Step-by-step explanation:

There are two outcomes that are included in the event "2 different in color" -- either Red followed by Blue (RB) or Blue followed by Red (BR).

Probability of RB is $\frac{5}{11}\times \frac{6}{11}=\frac{30}{121}$ The denominator 11 does not change in the second fraction because you put the first marble back; still 11 marbles in the bag.

Probability of BR is $\frac{6}{11} \times \frac{5}{11}=\frac{30}{121}$

Probability of RB <u>or</u> BR: add the probabilities to get 60/121.

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The sales tax in your city is 8.8%, point, 8, percent, and an item costs $63$, before tax.

PIT_PIT [208]

You would pay $5.54 on that item.

Step-by-step explanation:

Given,

Cost of item = $63

Sales tax rate = 8.8%

Amount of sales tax = 8.8% of cost of item

Amount of sales tax = $\frac{8.8}{100}*63$

Amount of sales tax = $\frac{554.4}{100}$

Amount of sales tax = $5.54

You would pay $5.54 on that item.

Keywords: percentage, division

Learn more about percentages at:

#LearnwithBrainly

8 0

4 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

What is 1.950 as a mixed number

deff fn [24]

1.950= 1 95/100= 1 19/20

3 0

3 years ago

Use the law of cosines to find the length of a

borishaifa [10]

Answer:

Step-by-step explanation:

You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:

$\frac{sin55}{175}=\frac{sin42}{a}$ and solving for a:

$a=\frac{175sin42}{sin55}$ so

a = 143.0

4 0

3 years ago

4a-(a+6)=12-36 please help i am confused again lol

andreev551 [17]

Answer:

a=6

Step-by-step explanation:

4 0

3 years ago