1) 8n - 40 = 6(8 + 5n)

2 answers:

8 0

$\text{Hello there!}\\\\\text{Solve for n:}\\\\8n - 40 = 6(8 + 5n)\\\\\text{First, distribute the 6 to the variables inside the parenthesis}\\\\8n-40=48+30n\\\\\text{Subtract both sides by -30n}\\\\-22n-40=48\\\\\text{Add 48 to both sides}\\\\-22n=88\\\\\text{Divide both sides by -22}\\\\n=-4\\\\\boxed{n=-4}$

xxMikexx [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Isolate n on one side of the equation.

DISTRIBUTIVE PROPERTY:

A(B+C)=AB+AC

A(B-C)=AB-AC

6(8+5n) (First, expand by using distributive property.)

6*8=48

6*5n=30n

48+30n

8n-40=48+30n

8n-40+40=48+30n+40 (Next, add 40 from both sides.)

48+40 (Solve.)

48+40=88

8n=30n+88

8n-30n=30n+88-30n (Subtract 30 from both sides.)

8n-30n (Solve.)

8n-30n=-22n

-22n=88

-22n/-22=88/-22 (Then, divide by -22 from both sides.)

88/-22 (Solve.)

88/-22=-4

n=-4

Therefore, the final answer is n=-4.

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An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number

vovikov84 [41]

Answer:

The number of key rings sold on a particular day when the total profit is $5,000 is 4,000 rings.

Step-by-step explanation:

The question is incomplete.

An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number of key rings is given by

$P=n^2-2n-3$

where n is the number of key rings in thousands.

Find the number of key rings sold on a particular day when the total profit is $5,000.

We have the profit defined by a quadratic function.

We have to calculate n, for which the profit is $5,000.

$P=n^2-2n-3=5\\\\n^2-2n-8=0$

We have to calculate the roots of the polynomial we use the quadratic equation:

$n=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\n= \frac{-2\pm\sqrt{4-4*1*(-8)}}{2}= \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{36}}{2} =\frac{-2\pm6}{2} \\\\n_1=(-2-6)/2=-8/2=-4\\\\n_2=(-2+6)/2=4/2=2$