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3 years ago

7

Help me Can somebody help me

1 answer:

Andrew [12]3 years ago

8 0

Answer:

7) 1/4, 1/2, 5/8, 3/4, 7/8. This is in the right order.

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If the demand for a product decreases, what is likely to happen?

3241004551 [841]

Answer: D. The price is likely to decrease.

Explanation: Supply and Demand, when a product is in high demand, which means a lot of consumers want it then companies can raise the price on it. When its in low demand then they have to decrease the price in order for that product to sell.

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3 years ago

Factor completely:<br> 21) x2 – 2x - 8

mojhsa [17]

Answer: x = -2 and 4

Step-by-step explanation:

x^2 - 2x - 8 = 0

(x - 4)(x + 2) = 0

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3 years ago

Find the number of DEGREES rotated in a circle of radius 6 inches if an arc is created with a length of 11(pi) inches

artcher [175]

Radius = 6 inches

Arc lenght = 11pi inches

Degrees ?

Arc lenght = radius x angle in radians

A = r * a

Solving for a:

a = A/r = 11pi/6 = 5.759586532 radians

5.759586532 to degrees ==> a = 330 degrees

Answer:

330 degrees

3 0

1 year ago

Missing fraction<br> blank + 1/16 = 3/2

skad [1K]

Answer: 1/2

Step-by-step explanation:

Let the missing fraction be x

x + 1/16 = 3/2

Make x the subject by subtracting both sides by 1/16

x = 3/2 - 1/16

x= 24 - 16/16

= 8/16; divide through by a common value of 8

x = 1/2

I hope this helps.

4 0

3 years ago

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago