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kipiarov [429]
3 years ago
13

Simplify: 14 1/4−12 4/5

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer:

1.45

Step-by-step explanation:

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Find the solution to this inequality.
Nina [5.8K]

Answer:

I'm not sure exactly what this means, but I think I have an idea.

Fraction form: -1x > -3/2x

Decimal form: -1x > -1.5x

<em>(Again, I'm not completely sure what the question is asking for, but I think I have seen it before.)</em>

3 0
3 years ago
PLEASE ANSWER, WILL MARK CORECT ANSWER BRAINLIEST
Anna007 [38]

Answer:

B, D

Step-by-step explanation:

-3(0.15 - 0.2 +0.25p) = -3(-0.05 +0.25p) = 0.15-0.75p

A doesn't work because -3(0.15 - 0.2 +0.25p) = -0.45+0.6-0.75

C doesn't work because 3(0.15+0.2+0.25p) = 0.45+0.6+0.75 which doesn't equal -0.45+0.6-0.75.

E doesn't work because 0.15-0.2 = -0.05 not 0.05.

4 0
3 years ago
Read 2 more answers
Consider a student loan of ​$20,000 at a fixed APR of 12​% for 15 years. a. Calculate the monthly payment.​(Do not round until t
joja [24]

Answer:

a. $240.03

b. $43,205.04

c. Principal = 46.29%

   Interest = 53.71%

Step-by-step explanation:

The computation is shown below:

a. For computing the monthly payment we need to apply the PMT formula i.e to be shown in the attachment below

Given that,  

Present value = $25,000

Future value or Face value = 0

RATE = 12% ÷ 12 months = 1%

NPER = 15 years × 12 months = 180 months

The formula is shown below:  

= PMT(RATE;NPER;-PV;FV;type)  

The present value come in negative  

So, after applying the above formula the monthly payment is $240.03

b. Now the total amount paid is

= Monthly payment × time period

= $240.03 × 180 months

= $43,205.04

c. Now the percentage is

For principal

= $25,000 ÷ $43,205.04 × 100

= 46.29%

And, for the interest, it is

= 100% - 46.29%

= 53.71%

6 0
3 years ago
Please help need a 100
aivan3 [116]

I'd have to say it's A. Please don't blame me if I'm wrong. :)

4 0
4 years ago
How much is 5 divided by 4.9​
jok3333 [9.3K]

Answer:

1.02

Step-by-step explanation:

8 0
3 years ago
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