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kipiarov [429]
3 years ago
13

Simplify: 14 1/4−12 4/5

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer:

1.45

Step-by-step explanation:

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What is the solution to the equation = 25?<br><br> x = 5<br> x = 10<br> x = 25<br> x = 125
Brilliant_brown [7]

Answer:

x=125

Step-by-step explanation:

To solve we must find a number that when divided by 5 equals 25.

To do this we can either...

Take each answer choice and plug in the value into the x spot and see if it works...

5/5=25  WRONG

10/5=25 WRONG

25/5=25 WRONG

125/5=25 CORRECT!

ORRR... we can set the equation so that the x is alone on one side.

To do this we can multiply both sides by 5

\frac{x}{5}=25 ---> x=25×5

x=125

7 0
2 years ago
Identify the GCF of 9a^4b^4-27a^3b^3+18a^3b^2
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Hello,

To solve, factour out the expression: <span>9a^4b^4-27a^3b^3+18a^3b^2.

Once factoured out you get the GCF 9a^(3)b^(2)


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3 0
3 years ago
A spinner of a board game can land on any one of three regions​labeled: A,​ B, and C. If the probability the spinner lands on B
Veseljchak [2.6K]

Answer:

The probability of the spinner landing on A is 0.1111.

Step-by-step explanation:

The possible outcomes of a board game is that it can lead on any three of the regions, A, B and C.

The probability of all the outcomes of an event sums up to be 1.

P(E) = P(E_{1})+P(E_{2})+...+P(E_{n})=1

According to the provided information:

P (B) = 3 P (A)

P (C) = 5 P (A)

Compute the probability of the spinner landing on A as follows:

P(A)+P(B)+P(C)=1\\P(A)+3P(A)+5P(A)=1\\9P(A)=1\\P(A)=\frac{1}{9}\\=0.111111\\\approx0.1111

Thus, the probability of the spinner landing on A is 0.1111.

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3 years ago
Which one of the following statements contains a quotient
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5 0
3 years ago
If a data value in a normal distribution has a negative z-score, which of the following must be true?
Tamiku [17]
<span>The data value must be less than the mean.</span>
4 0
3 years ago
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