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atroni [7]
3 years ago
10

A theater charges $5 for student tickets and $7 for adults tickets. They sold 75 tickets for a total of $425. Which set of equat

ions can be used to determine x, the number of students tickets sold, and y, the number of adult tickets sold?
Mathematics
2 answers:
Eduardwww [97]3 years ago
5 0
They sold 75 tickets total, so one of your equations will be x+y=75.

The other equation has to do with the price.
5x+7y=425.


Your two equations are:
x+y=75
5x+7y=425
Sophie [7]3 years ago
3 0
1.   5x+7y=$425
2.   (5*x)+(7*y)= $425
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Sav [38]

Answer:

14 miles

Step-by-step explanation:

Assuming each horse was only ridden once

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182 miles / 13 horses  = 14  miles  horse

Of course, if each horse was ridden more than once before being replaced the distance between replacements could be reduced.

Note that the fact that there were 3 riders is irrelevant.

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3 years ago
1. Do you the following side lengths form a right triangle?2. Which measurement is closest to the value of X in centimeters?
koban [17]

Answer:

Part 1:

Yes, the side lengths form a right triangle.

Part 2:

Option d 37.1 cm

Explanation:

We need to use the pythagorean theorem.

In part 1, if the 3 side lengths are a right triangle, then, they must verify:

7.5^2=4.5^2+6^2

By the theorem. Then:

\begin{gathered} 7.5^2=56.25 \\ 4.5^2+6^2=20.25+36=56.25 \end{gathered}

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For part 2, we need to use again the theorem. In this case:

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6 0
1 year ago
The wholesale price for a shirt is 3.50 A certain department store marks up the wholesale price by 90% Find the price of the shi
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3 years ago
Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose
yawa3891 [41]

Answer:

V=5\sqrt{3}\ m^3

Step-by-step explanation:

we know that

The volume of a trough is equal to

V=BL

where

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step 1

Find the area of  equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

B=\frac{1}{2} b^{2} sin(60\°)

where

b=2\ m

sin(60\°)=\frac{\sqrt{3}}{2}

substitute

B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})

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step 2

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substitute

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3 years ago
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