Answer:
The rate at which the total income is increasing is$1627415600
Step-by-step explanation:
From the given data
Population in the area=P=961400
The rate of increase in population=dP/dt=9200
The Average Income=I=$30593
The rate of increase in Average Income=dI/dt=$1400
Now the total income is given as
Total Income=TI=PI
So the rate of increase of total personal income is given as ![\frac{d}{dt}(PI)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%28PI%29)
From the product rule of derivatives
![\frac{d}{dt}(P*I)=I*\frac{dP}{dt}+P*\frac{dI}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%28P%2AI%29%3DI%2A%5Cfrac%7BdP%7D%7Bdt%7D%2BP%2A%5Cfrac%7BdI%7D%7Bdt%7D)
Here
I is the Average Income which is given as $30593
dI/dt is the rate of increase of income which is given as $1400.
P is the population of the area which is given as 961400
dP/dt=9200 is the rate of increase of population which is given as 9200
By substituting the values,
![\frac{d}{dt}(P*I)=I*\frac{dP}{dt}+P*\frac{dI}{dt}\\\frac{d}{dt}(P*I)=30593*9200+961400*1400\\\frac{d}{dt}(P*I)=\$1627415600](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%28P%2AI%29%3DI%2A%5Cfrac%7BdP%7D%7Bdt%7D%2BP%2A%5Cfrac%7BdI%7D%7Bdt%7D%5C%5C%5Cfrac%7Bd%7D%7Bdt%7D%28P%2AI%29%3D30593%2A9200%2B961400%2A1400%5C%5C%5Cfrac%7Bd%7D%7Bdt%7D%28P%2AI%29%3D%5C%241627415600)
So the rate at which the total income is increasing is$1627415600