A quadrilateral can not have obtuse angles.
Answer:
2x^2 + x - 1
If I did anything you didn't understand let me know so I can explain.
Step-by-step explanation:
All of them are quadratics so let's use that.
The first one is 2x^2 + x - 1. To find the axis of symmetry the strategy is usually to find the two zeroes of a quadratic and pick the number between them. Something to notice though is that 2x^2 + x - 1 is just 2x^2 + x sshifted down 1, so they both have the same axis of symmetry. So I am going to ignore the constant, because then finding the zeroes is much much simpler. I am going to do this with all opions.
So 2x^2 + x - 1 I am just going to use 2x^2 + x. If you factor out an x you get x(2x + 1) So now we have it in factored form and we know the zeroes are 0 and -1/2. The number directly in between these is -1/4, so the axis of symmetry is x = -1/4. I don't know if there is only one with that axis of symmetry so i am going to check the rest.
2x^2 - x + 1 means we are only going to look at 2x^2 - x. factoring we get x(2x - 1) so the zeroes are 0 and 1/2, so the axis of symmetry is at 1/4.
x^2 + 2x - 1 we only use x^2 + 2x. Factored form is x(x+2) so zeroes are 0 and -2 whichh means axis of symmetry is -1
x^2 - 2x + 1 has the same axis of symmetry as x^2 - 2x, which has zeros at 0 and 2 so the axis of symmetry is at 1.
So yep, it was just the first one.
$7, I think. I would not be too sure about it, though.
(x+1)(x-4)-(x-2) = 0
x²-4x+x-4-x+2 = 0
x²-4x-2 = 0
/\ = (-4)² - 4*1*(-2)
/\ = 16 + 8
/\ = 24
x = (-(-4)+/- \/24) / 2
x = (4+/-\/4*6)/2
x = (4+/-2\/6)/2
x = 2+/-\/6
x' = 2+\/6
x" = 2-\/6
Answer:
Gradient=¾
Step-by-step explanation:
Write the equation in slope-intercept form y=mx+c
3x-4y=24
-4y=24-3x
y=24/-4-3x/-4
y=-6+¾x
y=¾x-6
The gradient is therefore ¾
The y-intercept of the line occurs at(0,-6)
The x-intercept of the line occurs at(8,0)
Finding the midpoint of the two intercepts
{(x1+x2)/2,(y1+y2)/2}
M={0+8/2,(-6+0/2)}
M={8/2,-6/2}
M=(4,-3)
As you can see, the other information was not required to solve it
