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3 years ago

Submit 10

Mathematics

1 answer:

kenny6666 [7]3 years ago

7 0

Answer:

The equation required to find Width of rectangle is: $\mathbf{24=2x+2}$

Step-by-step explanation:

Area of rectangular table top = 24 ft^2

Let width of table = x

Length of table = x+2

We need to find equation that could be used to find the width (w) of the table top?

The formula used is: $Area\:of\:rectangle=Length \times Width$

Putting values in formula and finding the equation:

$Area\:of\:rectangle=Length \times Width\\24=x+x+2\\24=2x+2\\$

So, the equation required to find Width of rectangle is: $\mathbf{24=2x+2}$

The options given are not complete. So please verify your answer.

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The figure below shows a line graph and two shaded triangles that are similar:

VLD [36.1K]

Every time the y-value decreases by 1, the x-value increases by 2, so the slope is -1/2 throughout the line.

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3 years ago

Read 2 more answers

Determine the x- and y-intercepts of the graph ofx−4y=8Then plot the intercepts to graph the equation.

Over [174]

The x-intercept is the point where the graph cuts the x-axis, and the y-intercept is the point where the graph cuts the y-axis.

The x-axis is the line y = 0 and the y-axis is the line x = 0. To find the intercept between each axis and our graph, we just need to evaluate our function at x = 0 and y = 0.

Calculating the x-intercept, we have

$\begin{gathered} x-4\cdot0=8 \\ x=8 \end{gathered}$

The x-intercept is (8, 0).

Calculating the y-intercept, we have

$\begin{gathered} 0-4y=8 \\ y=-\frac{8}{4} \\ y=-2 \end{gathered}$

The y-intercept is (0, -2).

8 0

1 year ago

Only one of the comparisons below is correct. Which is correct? What benchmark was used in your answer?

tiny-mole [99]

Answer:

2/3<9/10; I used 3/4 as a benchmark.

Step-by-step explanation:

2/3<1/2; I used 1/2 as a benchmark.

2/3 = 0.(20/3) = 0.667

1/2 = 0.(10/2) = 0.5

So this is wrong, as 0.667 > 0.5.

1/2=3/5; I used 1/4 as a benchmark.

1/2 = 0.(10/2) = 0.5

3/5 = 0.(30/5) = 0.6

0.5 != 0.6, so this is wrong.

2/3<9/10; I used 3/4 as a benchmark.

2/3 = 0.(20/3) = 0.667

9/10 = 0.(90/10) = 0.9

So this is correct, as 0.667 < 0.9

3/4<2/3; I used 1/2 as a benchmark.

3/4 = 0.(30/4) = 0.75

2/3 = 0.(20/3) = 0.667

0.75 > 0.667, so this is wrong.

5 0

3 years ago

Consider vectors u and v, where u = (1, -1) and v = (1, 1). What is the measure of the angle between the vectors?

7nadin3 [17]

Answer:

I believe the answer is C. 90 degrees

Step-by-step explanation:

First you find the lengths of the two vectors, which are both $\sqrt{2}$ . Then you find the angle given the cos using: cos(∅)= $\frac{u*v}{|u|*|v|}$ = $\frac{0}{\sqrt{2}*\sqrt{2} }$ = 0. Then using ∅=acos(0)= $\frac{\pi }{2}$ = 90°