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Lapatulllka [165]
3 years ago
8

A cone with radius 6ft and a height of 12ft

Mathematics
1 answer:
Kisachek [45]3 years ago
3 0
If you are looking for the volume, plug the values into the equation for the volume of a cone which is 1/3(pie)r^2h. So where r is the radius and h is the height, your answer would be 452.389 cubic feet
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What is the end behavior of y=-2x^13+25x^8-3 as x approaches infinity?
RUDIKE [14]
Odd degree and negative leading coefient
means it goes from the top left to bottom right
goes infinitely down

as x aproaches infinity, y approaches neagtive infinity

6 0
3 years ago
Given the trinomial, what is the value of the coefficient B in the factored form? 2x2 + 4xy − 48y2 = 2(x + By)(x − 4y) −12 12 −6
Sonja [21]

Answer:

B is 6.

Step-by-step explanation:

We are trying to find a value for B such that:

2x^2+4xy-48y^2=2(x+By)(x-4y) is true for every x,y.

So let's choose x=0,y=1:

2(0)^2+4(0)(1)-48(1)^2=2(0+B(1))(0-4(1))

2(0)+0-48=2(B)(-4)

0-48=-8B

-48=-8B

Divide both sides by -8:

\frac{-48}{-8}=B

6=B

B=6

Note: I didn't want to choose y to be 0 because the value of B would disappear from the equation. So you should be able to have chosen any x and y except for y=0 to solve the equation for B.

Check:

So let's check and use foil to multiply out the right hand side.

(x+6y)(x-4y)

x(x)+x(-4y)+6y(x)+6y(-4y)

x^2-4xy+6xy-24y^2

x^2+2xy-24y^2

There was a 2 in front of that multplicapltiation:

2(x+6y)(x-4y)

2(x^2+2xy-24y^2)

2x^2+4xy-48y^2

This is exactly what we have on the left hand side of your given equation.

3 0
3 years ago
If Jefferson is drawing cards from a deck, and draws a 4 of hearts and a 10 of diamonds, what is this situation considered?
katrin2010 [14]
<h3>Answer:  A) Outcome</h3>

==========================================================

Explanation:

We can rule out "theoretical probability" since that concept deals with doing the math on paper, rather than getting out an actual deck of cards to compute the probability. If your teacher stated "the probability of drawing an ace is 1/13", then s/he would be using theoretical probability. We have a 1 in 13 chance to theoretically pick an ace out of all 52 cards since 4/52 = 1/13. No cards are needed to do such calculations. But if you actually pull out a deck of cards and randomly select them, then you'd be leaning toward empirical or experimental probability.

So in short, we can rule out choice B.

We can also rule out "complement" since the two situations of "drawing a 4" and "drawing a 10" aren't opposite. If it said something like "drawing a red card or drawing a black card", then those two events are opposite. The two events fully compose all the deck of cards (sample space). You either will draw a red one, or a black one, but not both colors at the same time.

So we're down to the answer being either A) outcome or D) event. At first glance, these two terms seem almost identical. However, they mean slightly different things.

Let's pick apart what each of those terms mean.

----------------

The outcome is the result of an event. An event is some specific action that you may or may not want to happen, and it's usually phrased within the parameters your teacher set up.

For example, we can define the event "it rains outside". So we're setting up the specific action of raining. Whether we want it or not doesn't really matter. The outcome would be the actual result of if the event happens or not. So if it does truly rain on day 1, then the outcome "rain" is what is recorded for day 1. Then if its dry on day 2, then "no rain" is the outcome for that second day. And so on.

Going back to the cards, one event could be set up as "selecting a heart card" with the outcome being "selected a 4 of hearts". The event is the rule set up and the outcome is the result we observe. To compute the empirical or experimental probability, we divide the number of times we get a specific event to occur over the total number of possible

---------------

Let's look at another example.

We'll roll a single die that has 6 faces on it. The set of possible outcomes are {1,2,3,4,5,6}. Only one outcome is possible per roll.

If we roll the die and it lands on 5, then the outcome is 5. This is the final result of the trial or experiment.

We can define an event like "A = rolling an even number", and then ask the question "what is the probability event A occurs?" In other words, we would be asking "what is the probability of rolling an even number?"

---------------

I suppose now that I think about it, we can state,

  • outcome = some single action you observe
  • event = collection of outcomes (usually some pattern to it)

as a loose way of telling the difference between the two terms.

Ultimately, the observations of getting a 4 of hearts and 10 of diamonds are considered an outcome.

4 0
3 years ago
Plis help me on how much you can thank you first to reply gets brainless
victus00 [196]

Answer:

yeet

Step-by-step explanation:

yeet yeet yeet yeet yeet yeet yeet yeet yeet eet yett yeet yeet yeet yeet yeet yeet yeet yeet yeety

6 0
2 years ago
I need help with geometry project
vekshin1

Answer:

...

Step-by-step explanation:

oki?

8 0
3 years ago
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