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3 years ago

What is the area of this figure? ___ units^2

Mathematics

1 answer:

enot [183]3 years ago

5 0

Answer:

$42\ units^{2}$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of a rectangle plus the area of two triangles

Find the area of rectangle

Observing the graph

The area of rectangle is equal to

$A=bh=(2+5)(2+2)=28\ units^{2}$

Find the area of the top triangle

$A=\frac{1}{2}bh=\frac{1}{2}(2+5)(4-2)=7\ units^{2}$

Find the area of the bottom triangle

$A=\frac{1}{2}bh=\frac{1}{2}(2+5)(-2+4)=7\ units^{2}$

the area of the figure is equal to

$A=28\ units^{2}+7\ units^{2}+7\ units^{2}=42\ units^{2}$

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Alisiya [41]

Answer:

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Step-by-step explanation:

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Is this correct ? check plsss...

d1i1m1o1n [39]

This looks one hundred percent correct to me and to check your answer you can plug in the answer you find to the first equation

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Read 2 more answers

What two decimals equivalent to 4.200

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3 years ago

A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 85% confidence inter

Gre4nikov [31]

Answer:

$7.3-1.440\frac{1.2}{\sqrt{830}}=7.240$

$7.3+1.440\frac{1.2}{\sqrt{830}}=7.360$

So on this case the 85% confidence interval would be given by (7.2;7.4)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=7.3$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma =1.2$ represent the population standard deviation

n=830 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

Since the Confidence is 0.85 or 85%, the value of $\alpha=0.15$ and $\alpha/2 =0.075$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.075,0,1)".And we see that $z_{\alpha/2}=1.440$