Question

20 PTS

Answer 1

We know that:

$MV_1=(2,16)\\\\MV_2=(-3,5)$

so the distance:

$d(MV_!,MV_2)=\sqrt{(-3-2)^2+(5-16)^2}=\sqrt{(-5)^2+(-11)^2}=\\\\=\sqrt{25+121}=\sqrt{146}\approx\boxed{12.1}$