Question

Find the distance between A(–3, 5) and B(4, 2), to the nearest hundredth.

Answer 1

Answer:

$d=7.62$

Step-by-step explanation:

Start with the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Identify your values.

$x_1=-3\\x_2=4\\y_1=5\\y_2=2$

Substitute.

$d=\sqrt{(4-(-3)^2+(2-5)^2}$

The $-3$ becomes positive as it's being multiplied by a negative.

$d=\sqrt{(4+3)^2+(2-5)^2}$

Solve what is in parentheses.

$d=\sqrt{(7)^2+(-3)^2}$

Square what is in parentheses.

$d=\sqrt{49+9}$

Add.

$d=\sqrt{58}$

Find the square root (I usually do four digits after the decimal).

$d=7.6157$

Round to the nearest hundredth.

$d=7.62$