3 students are selected from a class that has 10 boys and 5 girls. what is the probability that 1 boy and 2 girls are selected?

1 answer:

Nookie1986 [14]3 years ago

4 0

Chances of drawing a boy the first time = 12/16.
Chances of drawing a boy the second time = 11/15. 
Chances of drawing a boy the third time = 10/14. 

(12/16)(11/15)(10/14) = about 39.3%.

You might be interested in

PLEASE HELP! i would really appreciate it thank you

LiRa [457]

Answer:

Step-by-step explanation:

5 0

3 years ago

Rob notices that 55 percent of the people leaving the supermarket chhose plastic bags instead of paper bags. out of 600 people,

Temka [501]

To solve this answer, you are trying to find 55% of 600, because that is the number of people who chose plastic bag.

55% can be re-written as 55/100 OR 0.55 since percentages are always out of 100.

So, we do 0.55*600, which gives us 330. 330 people carry plastic bags.

4 0

3 years ago

Which southern in their boxes shows has a greater value

suter [353]

Answer: C) They have equal volumes

Step-by-step explanation:

Volume of Rectangular Prism = length x width x height

Green: 4 x 2 x 2 =16

Purple: 8 x 2 x 1 = 16

8 0

3 years ago

Read 2 more answers

How many different combinations of pennies, nickels, dimes, quarters, and half dollars can a piggy bank contain if it has 20 coi

ycow [4]

Because there are 20 coins plus four bars = 24 items to choose. You want to choose where to put the four bars, thus C(24,4). There are four bars, not five. Note that four bars divide the 20 coins into five sections. Five bars would divide it into six, but we only have five different kinds of coins to choose from.

5 0

3 years ago

Jon is launching rockets in an open field. The path of the rocket can be modeled by the quadratic function h(t) = -16t^2 + 96t,

IrinaVladis [17]

It will reach 80 feet for the second time after 5 seconds.

We set the equation equal to 80 feet:
80= -16t² + 96t

When solving quadratics, we want it equal to 0, so we subtract 80 from both sides:
80-80= -16t² + 96t - 80
0= -16t² + 96t - 80

We use the quadratic formula to solve:
$t=\frac{-96\pm \sqrt{96^2-4(-16)(-80)}}{2(-16)}
\\
\\t=\frac{-96\pm \sqrt{9216-5120}}{-32}
\\
\\t=\frac{-96\pm \sqrt{4096}}{-32}
\\
\\t=\frac{-96\pm 64}{-32}
\\
\\t=\frac{-96+64}{-32} \text{ or } 0=\frac{-96-64}{-32}
\\
\\t=1 \text{ or } t=5$

4 0

3 years ago