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RSB [31]
3 years ago
11

Which products are negative?

Mathematics
1 answer:
Aliun [14]3 years ago
3 0
Both A and D are negative products.
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An Isosceles triangle is shown below. What is the size of angle a°.
Sergeeva-Olga [200]

Step-by-step explanation:

without seeing a picture I'm guessing 45 45, and 90

4 0
2 years ago
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Solve the equality 2(4x+1 )< 3(2x-3)
Musya8 [376]

Answer:

Step-by-step explanation:

2(4x+1)<3(2x-3)

simplify to

8x+2<6x-9

we can add 9 to both sides and subtract 8x from both sides

11<-2x

divide by -2

-5.5>x

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2 years ago
Compare and contrast the rate 4/5 mile in 8 minutes and 4 minutes to travel 2/5 mile
Gwar [14]

The values of the rates 4/5 mile in 8 minutes and 4 minutes to travel 2/5 mile are equal

<h3>How to compare and contrast the rates?</h3>

The rates are given as:

Rate 1 = 4/5 mile in 8 minutes

Rate 2 = 2/5 mile in 4 minutes

Calculate the above rates

This is done as follows:

Rate 1 = 1/10 mile per minute

Rate 2 =1/10 mile per minute

When the rates are calculated, the values are 1/10 mile per minute

Hence, the values of the rates 4/5 mile in 8 minutes and 4 minutes to travel 2/5 mile are equal

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5 0
2 years ago
On Friday, a local hamburger shop sold a combined total of 309 hamburgers and cheeseburgers. The number of cheeseburgers sold wa
cupoosta [38]
Divide 309 by 3. You should get 103 (hamburgers). if you multiply that by 2 you will get 206 (cheeseburgers). Add the two together you get the total which was 309 originally.
103 hamburgers and 206 cheeseburgers.
3 0
3 years ago
Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3​
maria [59]

Answer:

        a_1=4\\\\a_2=0\\\\a_3=3

Explanation:

The equation is:

      a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}

and

      a_4=-7, a_5=-36, a_6=-85

<u>1. Subsittute n = 6 into the equation:</u>

      a_6=3a_{5}-5a_{4}-4a_{3}

      Now subsititute the known values:

       -85=3(-36)-5(-7)-4a_{3}

      You can solve for a_3

      -85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3

<u />

<u>2. Substitute n = 5 into the equation:</u>

    a_5=3a_{4}-5a_{3}-4a_{2}

     Substitute the known values and solve for a_2

        -36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0

<u>3. Substitute n = 4 into the equation, subsitute the known values and solve for </u>a_1<u />

       a_4=3a_{3}-5a_{2}-4a_{1}

        -7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4

7 0
3 years ago
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