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4 years ago

The price of an item has been reduced by 40%. The original price was $55. What is the price of the item now?

Mathematics

2 answers:

valkas [14]4 years ago

5 0

Im so sorry need point for this test I have 5 minutes left

Dafna1 [17]4 years ago

3 0

Answer:

40% of 55 is 22

Step-by-step explanation:

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1(4 – 22); 2 – 2x I don’t get this question can someone help me

sertanlavr [38]

Answer:

i dont know if this is what u wanted but it wasn't really specified

Step-by-step explanation:

1(4 – 22); 2 – 2x

simplified:

−18;−2x+2

8 0

3 years ago

Pls welp will give brainliest to whoever answers correctly first

Sholpan [36]

There are 12 squares in each 4 x 3 grid.

25% of 12 = 3

This means that there should be 3 shaded squares in the grid.

Your answer is B. because it has 3 shaded squares.

7 0

3 years ago

Read 2 more answers

What is an equation of the line that passes through the point ( 6 , − 1 ) (6,−1) and is parallel to the line x − 3 y = 3 x−3y=3?

Nataly [62]

Answer:

y = 1

Step-by-step explanation:

Passes through (6,-1)(6,-1)

Find the slope (m)

m=(y2 - y1) / (x2 - x1)

m=(-1 - (-1) ) / (6-6)

m= 0

Parallel to x - 3y = 3

-3y = -x +3

y = 1/3 x -1

Equation of the line equation is y - y1 = m ( x - x1 )

y - ( -1 ) = 0 ( x - 6 )

y + 1 = 0

y = 1

4 0

3 years ago

A simple random sample of size has mean and standard deviation.Construct a confidence interval for the population mean.The param

scZoUnD [109]

ANSWER:

EXPLANATION:

A simple random sample of size has mean and standard deviation. Construct a confidence interval for the population mean. The parameter is the population The correct method to find the confidence interval is the method.

The sample size is not given. Mean and Standard Deviation are not given.

To construct a confidence interval for the population mean, first find out the margin of error of the sample mean. This is why you need a confidence interval. If you are 90% confident that the population mean lies somewhere around the sample mean then you construct a 90% confidence interval.

This is equivalent to an alpha level of 0.10

If you are 95% sure that the population mean lies somewhere around the sample mean, your alpha level will be 0.05

In summary, get the values for sample size (n), sample mean, and sample standard deviation.

Make use of a degrees of freedom of (n-1).

7 0

3 years ago

A tank initially has 300 gallons of a solution that contains 50 lb. of dissolved salt. A brine solution with a concentration of

belka [17]

Let s(t) be the amount of salt in the tank at time t. Then s(0) = 50 lb.

Salt flows into the tank at a rate of

(2 gal/min) (6 lb/gal) = 12 lb/min

and flows out at a rate of

(2 gal/min) (s(t)/300 lb/gal) = s(t)/150 lb/min

so that the net rate at which salt is exchanged through the tank is

ds(t)/dt = 12 - s(t)/150 … (lb/min)

Solve for s(t). The DE is separable, so we have

ds/dt = 12 - s/150

150 ds/dt = 1800 - s

150/(1800 - s) ds = dt

Integrate both sides to get

-150 ln|1800 - s| = t + C

Solve for s :

ln|1800 - s| = -t/150 + C

1800 - s = exp(-t/150 + C )

1800 - s = C exp(-t/150)

s = 1800 - C exp(-t/150)

Now given that s(0) = 50, we solve for C :

50 = 1800 - C exp(-0/150)

50 = 1800 - C

C = 1750

Then the amount of salt in the tank at any time t ≥ 0 is

s(t) = 1800 - 1750 exp(-t/150)

To find the time it takes for the tank to hold 100 lb of salt, solve for t in

100 = 1800 - 1750 exp(-t/150)

1700 = 1750 exp(-t/150)

34/35 = exp(-t/150)

ln(34/35) = -t/150

t = -150 ln(34/35) ≈ 4.348

So it would take approximately 4.348 minutes.

By the way, we didn't have to solve for s(t), we could have instead stopped with

-150 ln|1800 - s| = t + C

Solve for C - this C is not the same as the one we found using the other method. s(0) = 50, so

-150 ln|1800 - 50| = 0 + C

C = -150 ln|1750|

==> t = 150 ln(1750) - 150 ln|1800 - s|

Then s(t) = 100 lb when

t = 150 ln(1750) - 150 ln(1700)

t = 150 ln(1750/1700)

t = 150 ln(35/34)

t ≈ 4.348

5 0

3 years ago