Answer:
Please check the formatting when posting. I'm assuming these are the equations:
y=x^2 - 2
y=−x
Step-by-step explanation:
We can either graph the equations or solve them. I use graphing - see the attachment. The lines intersect at (-2, 2) and (1,-1)
<u>1. Graphing</u>
See attached graph
(-2, 2) and (1,-1) are the intersection points
<u>2. Solving</u>
y=x^2 - 2 Use y=−x in this equation:
-x = x^2 - 2
0 = x^2 + x - 2
0 = (x+2)(x-1)
x = -2 and +1
(-2, 2) and (1,-1) are the intersection points
Answer:
The correct option D.
Step-by-step explanation:
The given function is
Where f(d) is the height of the ball at horizontal distance d.
Put f(d)=0, to find the distance where the ball touch the ground.
Quadratic formula:
Using the quadratic formula we get
Therefore the ball is in air between d=-0.146 to d=9.146.
The distance can not be negative, therefore the ball remains in the air between d=0 to d=9.146.
Therefore the correct option is D.
