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jeyben [28]
3 years ago
14

A line that passes through (1, 7), (10, 1)

Mathematics
1 answer:
adoni [48]3 years ago
6 0
The slope-point form: y = mx + b

m-the slope:    m=\dfrac{y_2-y_1}{x_2-x_1}

(1;\ 7)\to x_1=1\ and\ y_1=7\\(10;\ 1)\to x_2=10\ and\ y_2=1

subtitute

m=\dfrac{1-7}{10-1}=\dfrac{-6}{9}=-\dfrac{2}{3}

The slope-point form: y-y_1=m(x-x_1)

subtitute

y-7=-\dfrac{2}{3}(x-1)\\\\y-7=-\dfrac{2}{3}x+\dfrac{2}{3}\ \ \ |add\ 7\ to\ both\ sides\\\\\boxed{y=-\frac{2}{3}x+7\frac{2}{3}}
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Point E is the midpoint of AB and point F is the midpoint of CD .
Gwar [14]

Answer:

# AB is bisected by CD

# AE = 1/2 AB

# CE + EF = FD

Step-by-step explanation:

* Lets talk about the mid point

- The mid-point of a segment is divided the segment into two

  equal parts

- The figure has line segment AB

- E is the mid-point of AB

∴ E divides the line segment AB into two equal parts

∴ AE = EB

∴ AE = 1/2 AB ⇒ (1)

- Any line passes through the point E will bisects the line segment AB

∴ AB is bisected by CD ⇒ (2)

∵ F is the mid-point of CD

∴ F divides the line segment CD into two equal parts

∴ CF = FD

∵ Point E lies on CF

∴ CE + EF = CF

∵ CF = FD

∴ CE + EF = FD ⇒ (3)

* There are three statements must be true (1) , (2) , (3)

# AB is bisected by CD

# AE = 1/2 AB

# CE + EF = FD

6 0
3 years ago
Read 2 more answers
A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

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V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

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E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0
3 years ago
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Answer:

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