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2 years ago

9

Point R′ (−2, 8) is the image of point R (−2, 2). Which of the following algebraic representations could be used for that transf

ormation?
Select one:

(x,y)→(−x,y)

(x,y)→(4x,4y)

(x,y)→(x,y+6)

(x,y)→(x+6,y)

1 answer:

insens350 [35]2 years ago

4 0

Answer:

C) (x,y) → (x,y+6)

Step-by-step explanation:

As the x value stays the same after the transformation, we know that there can be no changes to the value x, automatically limiting the options to answer C.

The mathematical way to find the value y is changed by would be by setting up a small equation as follows:

$8 = 2 + n$ , where n is some number that the y value is altered by.

Solving for n gives the value 6, proving that the translation must add 6 to the y value.

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6. If four numbers are in proportion, then the terms equals the product of<br>

snow_tiger [21]

Answer: If four numbers are proportional, a : b = c : d, then the product of the extremes is equal to the product of the means. ad = bc

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2 years ago

Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

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2 years ago

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nasty-shy [4]

Betty's height versus Jinlan's height is 2:3

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3 years ago

Please help im so confused

MArishka [77]

Answer:

i

Step-by-step explanation:

i = $\sqrt{-1}$

i^2 = -1

i^3 = -i

i^4 = 1

(Make sure you know your exponent rules)

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3 years ago