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slega [8]
3 years ago
7

At the movie theater, child admission is $5.30 and adult admission is 9.20. On Monday, four times as many adult tickets as child

tickets were sold, for a total sales of $1305.10 how many child tickets were sold that day?
Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0
124 tickets sold at $9.20 = $1140.80
124÷4 =31
31 tickets sold at $5.30 = $164.30
$1140.80+$164.30=$1305.10
so so if you take the 124 tickets and divide it by 4 you get 31. The answer is 31 rickets were sold that day.
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Write -7.32 as a Fraction/Mixed Number In Simplest Form. Also Show Steps To How You Got To Your Answer.
Mamont248 [21]

To write 7.32 as a fraction you have to write 7.32 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

7.32 = 7.32/1 = 73.2/10 = 732/100

And finally we have:  

7.32 as a fraction equals 732/100

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14-21 in lowest terms
BaLLatris [955]
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Expand and simplify:<br> a(a + 5)
RoseWind [281]

Answer:

a squared+ 5a

Step-by-step explanation:

a(a+5)

multiply everything inside the bracket

a times a is a squared

a times 5 is 5a

i hope i helped

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6 0
3 years ago
Can someone answer these pls!! I will be glad to have you answer them !! I need this done by tomorrow!
BARSIC [14]

Answer:

7/8=0.875   7/20=0.35   18/20=0.9    7/8=0.875    68/50=1.36     25/20=1.25 26/25=1.04   11/10=1.1     11/16=0.6875  9/16=0.5625  33/40=0.825  23/40=0.575   14/10=1.4     29/25=1.16  39/40=0.975

Step-by-step explanation:

5 0
3 years ago
Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).
Serjik [45]

Answer:

\displaystyle f(x)=x^2+2x+2

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

\displaystyle f(x)=ax^2+bx+c

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

\displaystyle f(-1)=a(-1)^2+b(-1)+c

\displaystyle f(-1)=a-b+c

\displaystyle a-b+c=1.....[eq\ 1]

Now we use the second condition f(1)=5

\displaystyle f(1)=a(1)^2+b(1)+c

\displaystyle f(1)=a+b+c

\displaystyle a+b+c=5.......[eq\ 2]

Finally, we use the third condition f(2)=10

\displaystyle f(2)=a(2)^2+b(2)+c

\displaystyle f(2)=4a+2b+c

\displaystyle 4a+2b+c=10....[eq\ 3]

We put together eq 1, eq 2, and eq 3 to form the system

\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.

Adding the first two equations we have

\displaystyle 2a+2c=6

\displaystyle a+c=3

And also

\displaystyle b=2

Using the above equation and the value of b in the third equation, we have

\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.

Subtracting the first equation from the second

\displaystyle 3a=3

\displaystyle a=1

And therefore

\displaystyle c=2

Now we have all the values, the quadratic function is

\displaystyle \boxed{f(x)=x^2+2x+2}

6 0
3 years ago
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