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Hitman42 [59]
3 years ago
8

Abby must create a three-character password for her computer the is two different, upper-case letters followed by one digit. if

she only is willing to use the letters in her first name and a digit in the current year(2011), how many possible passwords can she create? one possible password to include s YB1
Mathematics
1 answer:
velikii [3]3 years ago
5 0
The number of different permutations  of 2 letters from the name Abby 
= 3P2 =  3! / 3-2! = 3*2*1 = 6
Number of different  digits in 2011 = 3

Number of possible passwords = 6*3 = 18 (answer).
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We know that 15 binders = 22.50 dollars . We need to find the cost of 18, 30, 28, and 48 binders to figure out if they match up with the statements. One way to do this is to find the cost for one binder, and then multiply that by the number of binders to find the cost for a certain number of binders. For example, if one binder costs 2 dollars, five binders would cost 2 * 5 = 10 dollars.

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