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3 years ago

11

What is the value of the expression? –83

1 answer:

QveST [7]3 years ago

5 0

Value of an expression 8<span>3
</span>in where 8 is the base number and 3 is the exponent.
To get the answer, simply multiply the base number as many times as the exponent says.
Since the exponent is 3 and base is 8, we need to multiply 8 three times.
=> 8 x 8 x 8
<span>=> 512 </span>
Thus, the value of the given equation 83 is equals to 512
to check if our answer is correct, simply divide 512 by 8 twice.
<span>=> 512 / 8 </span>
=> 62 / 8
<span>=> 8</span>

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4 years ago

one pipe fills a store pool in 12 hours. A second pipe fills the same pool in 6 hours. When a third pipe is added and all three

Alina [70]

Answer:

x = 12 hours

Step-by-step explanation:

If one pipe fills store pool in 12 hours in 1 hour will fill 1/12 of the pool

If one pipe fills a store pool in 6 hours in 1 hour will fill 1/6 of the pool

Let call " x " number of hours needed by the third pipe to fills the pool

then in 1 hour will fill 1/x

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3 years ago

A man has n keys on a key ring, one of which opens the door to his apartment. Having celebrated a bit too much one evening, he r

schepotkina [342]

Answer:

The value is $P(3) = \frac{1}{n}$

Step-by-step explanation:

From the question we are told that

The number of keys is n

The number of keys remaining after the first key is chosen is n-1

The probability that he gains entrance with the first key he selects is $\frac{1}{n}$

Generally the probability that the first key does not open the door is

$p(F_1) = 1 - \frac{1}{n} = \frac{n-1}{n}$

Generally the number of keys remaining after the second key is chosen is

n-2

Generally the probability that he gains entrance with the second key he selects is

$\frac{1}{n-1}$

Generally the probability that the second key does not opens the door is

$P(F_2) = 1- \frac{1}{n-1} = \frac{n-2}{n-1}$

Generally the probability that he gains entrance with the third key he selects is

$\frac{1}{n-2}$

Generally the probability that the door opens with the third key

$P(3) = p(F_1) * P(F_2) * \frac{1}{n-2}$

=> $P(3) = \frac{n-1}{n} * \frac{n-2}{n-1} * \frac{n-2}{n-1}$

=> $P(3) = \frac{1}{n}$

Note :

All the outcome of the events are independent

7 0

4 years ago