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Setler79 [48]
3 years ago
6

Divide. -3 3/4 divided by 3

Mathematics
1 answer:
pickupchik [31]3 years ago
4 0

Answer:

A. -1\frac{1}{4}

Step-by-step explanation:

-3\frac{3}{4} \div 3 = -\frac{15}{4} \times \frac{1}{3} = -\frac{15}{12} = -1\frac{3}{12} = -1\frac{1}{4}

I am joyous to assist you anytime.

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Determine which postulate or theorem can be used to prove that ABC=DCB
lianna [129]

Answer with explanation:

In Δ ABC and ΔD BC

∠A=∠D-------Given

∠ABC=∠DCB-------Each being 90° given in the Diagram.

Side, BC is Common.

⇒⇒Δ ABC ≅ ΔD BC-------[AAS]

When two triangles are congruent , their areas are equal.

So, Area(ABC)=Area (DCB)

Option B :⇒ A AS

3 0
3 years ago
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Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

  • y=-(x+1)²+4

let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
3 years ago
SEE PHOTO
Xelga [282]

Answer:

b-m  b-c  b-r

Step-by-step explanation:

8 0
3 years ago
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Number 6 plz plz plz help
vagabundo [1.1K]

you could tell if it is even or odd by how many number are odd and how many are even...majority wins...

13 odd

45 odd

24 even

17 odd

hope i can help,and have a nice day!! :)

7 0
3 years ago
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(Sorry forgot to put picture)
Sliva [168]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
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