Answer:
1)2x^2 2)8x^3 3)4x-8
Step-by-step explanation:
1- you plug in x in g but nothing changes so then h and gyou just add 2- you plug in x in g again but once again, it remains the same so you just multiphy g and h and you get 8x^2 3- you plug in -2 into g to get 8 and then subtract it form h
Answer:1/5
Step-by-step explanation:
Round the . And get the answer
<h2><u>Solution</u>:-</h2>
• Surface area of a cylinder = 2πr(r + h) sq. units.
In the above diagram,
Radius (r) of the cylinder = 13 cm.
Height (h) of the cylinder = 39 cm.
<h3>• Taking value of π = 3.14</h3>
Hence, Surface area of the cylinder = 2 × 3.14 × 13(13 + 39)
Surface area of the cylinder = (81.64 × 52) cm²
Surface area of the cylinder = 4245.28 cm²
The surface area of the cylinder is <u>4</u><u>2</u><u>4</u><u>5</u><u>.</u><u>2</u><u>8</u><u> </u><u>cm²</u>. [Answer]
The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
<h3>How to determine the functions?</h3>
A quadratic function is represented as:
y = a(x - h)^2 + k
<u>Question #6</u>
The vertex of the graph is
(h, k) = (-1, 2)
So, we have:
y = a(x + 1)^2 + 2
The graph pass through the f(0) = -2
So, we have:
-2 = a(0 + 1)^2 + 2
Evaluate the like terms
a = -4
Substitute a = -4 in y = a(x + 1)^2 + 2
y = -4(x + 1)^2 + 2
<u>Question #7</u>
The vertex of the graph is
(h, k) = (2, 1)
So, we have:
y = a(x - 2)^2 + 1
The graph pass through (1, 3)
So, we have:
3 = a(1 - 2)^2 + 1
Evaluate the like terms
a = 2
Substitute a = 2 in y = a(x - 2)^2 + 1
y = 2(x - 2)^2 + 1
<u>Question #8</u>
The vertex of the graph is
(h, k) = (1, -2)
So, we have:
y = a(x - 1)^2 - 2
The graph pass through (0, -3)
So, we have:
-3 = a(0 - 1)^2 - 2
Evaluate the like terms
a = -1
Substitute a = -1 in y = a(x - 1)^2 - 2
y = -(x - 1)^2 - 2
Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
Read more about parabola at:
brainly.com/question/1480401
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Answer:
1100 - 0.04x
Step-by-step explanation:
0.07x + 0.11(10,000 - x)
0.07x - 0.11x +1100
-0.04x + 1100
