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jeyben [28]
3 years ago
7

Budget Question, please help

Mathematics
1 answer:
Alexandra [31]3 years ago
3 0
The correct answer is D
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Pls help!!!!The probability of hitting a target on a single trial is 40%,Find the probability of hitting the same target 5/8 tim
azamat
Probability hit=40%=4/10
probability no hit=1-p (hit)=1-4/10=6/10
probability= p(hit)+p(hit)+p(hit)+p(hit)+p(hit)+p (no hit)+p (no hit)+p (no hit)
probability=4/10×4/10×4/10×4/10×4/10×6/10×6/10×6/10
=0.0022
( I think but I'm not 100% sure)
6 0
3 years ago
Find the value of abc-def<br> (I need work shown)
makkiz [27]

Answer:

x = 2.5 cm

Step-by-step explanation:

In Similarity triangles, the ratio of corresponding sides of the triangles are in same.

       \sf \dfrac{AC}{BC}=\dfrac{DF}{EF}\\\\\\\dfrac{x}{2}=\dfrac{11.5}{9.2}\\\\\\x = \dfrac{11.5}{9.2}*2\\\\x = 2.5 \ cm

4 0
2 years ago
Read 2 more answers
Question Help A television programmer is arranging the order that five movies will be seen between the hours of 6 P.M. and 4 A.M
Mamont248 [21]
<span>During the indicated time block of 6 PM-4 AM, the movies should go as follows: Since the G rating movies needs to be shown during the first time block, it would be first at 6 pm until around 8 pm. The NC-17 movie would also need to be LAST and from 2 am to 4 am. That leaves 3 movies left to be shown from around 8 pm to 2 Am, which could be shown in 6 different ways. If we assigned EACH movie a title of A, B or C, you get these different showing possibilities- ABC, ACB, BAC, BCA, CAB, and CBA. Since the first and last movies never change, they would default to the first and last positions while the rest is filled in.</span>
6 0
3 years ago
Which of the following expressions is equal to sin⁡(-150°)?
maria [59]

Check the picture below.

let's notice that the angle -150° has a reference angle of 30°, so any trigonometric function for either angle will be the same value, however, let's recall that the sine or y-coordinate is negative on the III Quadrant, so sin(-150°) is the same as sin(30°) BUT negative, -sin(30°).

7 0
3 years ago
Solve the following equation for 0° ≤ θ &lt; 360°. Use the "^" key on the keyboard to indicate an exponent. For example, sin2x w
never [62]

<u>Answer-</u>

\boxed{\boxed{x=90^{\circ},270^{\circ}}}

<u>Solution-</u>

The given equation-

\Rightarrow 2\sin^2 x-\cos^2 x-2=0

As

\sin^2 x+\cos^2 x=1\ \ \Rightarrow \cos^2 x=1-\sin^2 x

Putting this,

\Rightarrow 2\sin^2 x-(1-\sin^2 x)-2=0

\Rightarrow 2\sin^2 x-1+\sin^2 x-2=0

\Rightarrow 3\sin^2 x-3=0

\Rightarrow 3\sin^2 x=3

\Rightarrow \sin^2 x=1

\Rightarrow \sin x=\sqrt1

\Rightarrow \sin x=\pm 1

\Rightarrow \sin x=1,\ \sin x=-1

\Rightarrow x=\sin^{-1}(1),\ x=\sin^{-1}(-1)

\Rightarrow x=90^{\circ}+n360^{\circ},\ x=270^{\circ}+n360^{\circ}

Where n=0, 1, 2, ......

As given 0° ≤ x < 360°, so putting n = 0

\Rightarrow x=90^{\circ},\ x=270^{\circ}


3 0
4 years ago
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