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3 years ago

What is the value of x? x + (-10) = 2 Enter your answer in the box

2 answers:

lisabon 2012 [21]3 years ago

6 0

To get x by itself you would add 10 to each side to get x=12 because you do the opposite on the x side to the other side to get x by itself.

RideAnS [48]3 years ago

3 0

Answer:

Answer:

x=12

Step-by-step explanation:

x−10+10=2+10

x=12

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Hey friends answer this please Please give the letter choice

Aliun [14]

$1.2\cdot 10^{-3}-2.0\cdot 10^{-4}=1.2\cdot 10^{-3}-0.20\cdot 10^{-3}\\\\=1.0\cdot 10^{-3}$

The appropriate choice is ...

... D) 1.0×10⁻³ inch

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3 years ago

If ln(4x+y)=2x-3,then dy/dx=

Viktor [21]

$\ln(4x+y)=2x-3$

Differentiate both sides wrt $x$ :

$\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}$

By the chain rule, we get

$\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2$

$\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2$

Solve for $\frac{\mathrm dy}{\mathrm dx}$ :

$4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y$

$\boxed{\dfrac{\mathrm dy}{\mathrm dx}=8x+2y-4}$

4 0

3 years ago

I NEED HELP WITH ME MATH

ruslelena [56]

ok so lets start of with the fact that the whole thing is 21 units.

So we do 21-9=12 so then we now know that the rectangle is 12 so then we do 12*8 units which is= 96 . Now the triangles. so the first one we know that its 8*3 and times it by 1/2 because two triangles is equal to a rectangle so the first triangle is 12 and now the second. its 9-3= 6 then its 6*8*1/2 which is equal to 24 so now the final answer is

96+12+24 which is equal to 132 so i'm guessing it 132 square units

5 0

3 years ago

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

x = 2
y = -1

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

4 0

3 years ago

Math Help Please....

stich3 [128]

Triangle ABE is similar to triangle CED (AAA)
10/8 = (2x+6) / (x+6)
x=2
therefore AE = 2(2) + 6
= 10 units

5 0

3 years ago