You add all those number together then divide the number you got by how many numbers there are and that's your answer, 61.1
edit : dont listen to me I didnt see the numbers 64 and 65, im sorry
Answer:
Step-by-step explanation:
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<h2>
Greetings!</h2>
Answer:
6a + 1
Step-by-step explanation:
First, you need to multiply everything in the brackets by 3L
(7 + 2a) x 3 =
7 * 3 = 21
2a * 3 = 6a
21 + 6a
Now you can subtract the 20 from this:
6a + 21 - 20
Simplified down:
6a + 1
<h2>Hope this helps!</h2>
Answer:
20
Step-by-step explanation:
Sn = (n/2)(a1 + a1 + d(n-1)), where S = sum, a1 = first term, n = number of terms, d = common difference
400 = (n/2)(1 + 1 + 2(n - 1))
400 = (n/2)(2 + 2n - 2)
400 = (n/2)(2n
400 = n2
20 = n
Twenty numbers are in the set.
Answer:
Problem 8 is No and Problem 9 is Yes