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AnnZ [28]
3 years ago
11

Find the equation of the axis of symmetry for the parabola y = x^2 .

Mathematics
2 answers:
natka813 [3]3 years ago
7 0
X = 2x = 2 would be the answer
Tamiku [17]3 years ago
6 0
The vertex of the parabola is <span><span>(<span>2,1</span>)</span><span>(<span>2,1</span>)</span></span> .

So, the axis of symmetry is the line <span><span>x=2</span><span>x=2</span></span> .

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For what value of r is the parallelogram a rhombus
Gre4nikov [31]

Answer:

9

Step-by-step explanation:

7r+18=r²

r²-7r-18=0

factorizing

r²+2r-9r-18=0

r(r+2)-9(r+2=0

(r-9)(r+2)=0

r-9=0

r=9

check

(r²)=(9*9)=81

7r+18=7(9) + 8=81

5 0
3 years ago
Determine the x- and y- intercepts for the graph defined by the given equation.
777dan777 [17]

Answer:

y-intercept is (0,8)

c. x-intercept is (-8, 0)

Step-by-step explanation:

y=x+8

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7 0
3 years ago
Read 2 more answers
The radius of a circle is 7 mm. What is the area.
Solnce55 [7]

Answer:

A= 153.94 mm

Step-by-step explanation:

A = πr²

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A= 153.94 mm

7 0
2 years ago
In the diagram, the radius of the outer circle is
JulijaS [17]

the value of x is 8 cm.

<u>Step-by-step explanation:</u>

Correct Question : In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded region is 220π cm2. What is the value of x? Enter your answer in the box.

We have ,

the area of a circle =  πr²

the outer circle area = \pi(2x)^2 =4\pi x^2

the inside circle area = \pi (6)^2= 36\pi

According to Question,

the outer circle area - the inside circle area = he shaded region

⇒ \pi (4x^2)-36\pi =220\pi

⇒ x^2-9 =55

⇒ x^2=64

⇒x =\sqrt{64}=8

Therefore , the value of x is 8 cm.

5 0
2 years ago
Solve for x.38(2x+16)−2=13 Enter your answer in the box.x =
lys-0071 [83]

Given:

\frac{3}{8}(2x+16)-2=13\frac{3}{8}(2x+16)=13+2\frac{3}{8}(2x+16)=15(2x+16)=15\times\frac{8}{3}(2x+16)=402x=40-162x=24x=\frac{24}{2}x=12

5 0
1 year ago
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