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sasho [114]
3 years ago
10

In order for figure EFGH to be a trapozoid, which of the following must be true?

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0
You must connect all the letters to create the shape of a trapezoid


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What is the equation of the line that passes through the point (-6, -8) and has a slope of 1/3
ivanzaharov [21]

Answer <u>(assuming it can be in point-slope form)</u>:

y + 8 = \frac{1}{3} (x+6)

Step-by-step explanation:

With the given information, we can use the point-slope formula, y-y_1 = m (x-x_1), to write the equation of the line. Substitute values for the m , x_1, and y_1 in the formula to do so.

The m represents the slope, so substitute \frac{1}{3} in its place. The x_1 and y_1 represent the x and y values of one point the line intersects, so substitute -6 for x_1 and -8 for y_1. This gives the following answer and equation (just make sure to convert the double negatives into positives:  

y-(-8) = \frac{1}{3} (x-(-6))\\y + 8 = \frac{1}{3} (x+6)

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2 years ago
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Answer 1-6 (about square root)
Taya2010 [7]

Answer:

1. For a cube, volume = edge^{3}

2. \sqrt[3]{volume} = edge

3. Volume of the cube = 216 so, the edge = \sqrt[3]{216} = 6

4. 1st blank = 6

   2nd blank = 6

   3rd blank = 216

   4th blank = 216

5. 6 is the edge

6. As the room is a square and we have to find the side

Area = 121

Edge = \sqrt[2]{121} = 11

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Which of the following integrals cannot be evaluated using a simple substitution?
vitfil [10]
The third one, not sure about any other ones.
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cluponka [151]

Answer:

y = 2/3x - 3

Step-by-step explanation:

Step 1: Write equation

2x - 3y = 9

Step 2: Solve for <em>y</em>

  1. Subtract 2x on both sides: -3y = 9 - 2x
  2. Divide both sides by -3: y = -3 + 2/3x
  3. Rewrite: y = 2/3x - 3
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Carbon-14 has a half-life of 5730 years. In a plant fossil, you find that the 14C has decayed to 1/8.00 of the original amount.
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Note that 8.00 = (2.00)^3, that implies that a decay to 1/8.00 means that the Carbon-14 has passed 3 half-life. (1 to decay to 1/2, other to decay to 1/4, and other to decay to 1/8). And, three half-life is 3 * 5730 years = 17,920 years. So,<span> the answer is that the plant was alive 17,920 years.</span>
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