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Anna [14]
3 years ago
5

PLEASE HELP GIVI BRAINLIEST

Mathematics
1 answer:
fredd [130]3 years ago
7 0

Answer: B

Hope this helps ^-^

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The sum of two numbers is greater than 1. Which statement
Galina-37 [17]

Answer:

the sum of two whole numbers is always greater than either number because even if one of the numbers to be added is 0, the answer will, well, not be greater, but at least equal to it.

Step-by-step explanation:

plz mark as brainliest

5 0
3 years ago
Please give me answer friend<br>​
Law Incorporation [45]

Answer:

90°

Step-by-step explanation:

right angle - 90°

.....

5 0
3 years ago
Read 2 more answers
1/4(x-2)+4=12 <br> 1/4(x-2)=8<br> x-2=2<br> x=4 <br> correct the error
konstantin123 [22]

Step-by-step explanation:

(i) x + 3 = 0

L.H.S. = x + 3

By putting x = 3,

L.H.S. = 3 + 3 = 6 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ii) x + 3 = 0

L.H.S. = x + 3

By putting x = 0,

L.H.S. = 0 + 3 = 3 ≠ R.H.S.

∴ No, the equation is not satisfied.

(iii) x + 3 = 0

L.H.S. = x + 3

By putting x = −3,

L.H.S. = − 3 + 3 = 0 = R.H.S.

∴ Yes, the equation is satisfied.

(iv) x − 7 = 1

L.H.S. = x − 7

By putting x = 7,

L.H.S. = 7 − 7 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(v) x − 7 = 1

L.H.S. = x − 7

By putting x = 8,

L.H.S. = 8 − 7 = 1 = R.H.S.

∴ Yes, the equation is satisfied.

(vi) 5x = 25

L.H.S. = 5x

By putting x = 0,

L.H.S. = 5 × 0 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(vii) 5x = 25

L.H.S. = 5x

By putting x = 5,

L.H.S. = 5 × 5 = 25 = R.H.S.

∴ Yes, the equation is satisfied.

(viii) 5x = 25

L.H.S. = 5x

By putting x = −5,

L.H.S. = 5 × (−5) = −25 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ix) = 2

L.H.S. =

By putting m = −6,

L. H. S. = ≠ R.H.S.

∴No, the equation is not satisfied.

(x) = 2

L.H.S. =

By putting m = 0,

L.H.S. = ≠ R.H.S.

∴No, the equation is not satisfied.

(xi) = 2

L.H.S. =

By putting m = 6,

L.H.S. = = R.H.S.

∴ Yes, the equation is satisfied.

8 0
3 years ago
Read 2 more answers
A school held a special math event for parents. On the first night, 150 parents attended, which was 40% below the expected atten
Serga [27]

Answer:

10.429% exceed

Step-by-step explanation:

expected:

150x [100+40]/100=210 parents were expected on first night

210x60/100=126 parents expected on the second night

210+126=326 expected

percentage difference=

210+150=360

360/326 x 100=110,429%

110,429%-100%=10,429% exceed

4 0
3 years ago
Laura and Philip each fire one shot at a target. Laura has probability 0.4 of hitting the target, and Philip has probability 0.1
Pepsi [2]

Answer:

(i) 0.46, (ii)0.42, and (iii)0.143

Step-by-step explanation:

Let p be the probability of hitting the target and q be the probability of missing the target by Laura.

Given that p=0.4\;\cdots (1)

As Laura either hit or miss the target, so p+q=1.

\Rightarrow q=1-p=0.6 \; \cdots (2)

Again, let r be the probability of hitting the target and s be the probability of missing the target by Philip.

Here, r=0.1\;\cdots (3)

Similarly, \Rightarrow s=1-r=0.9\;\cdots (4)

(i)The probability that the target is hit means that the target is not missed by both, either of one or both hit the target.

=1-(probability of missing the target by both)

=1-qr [from equation (2) and (4) ]

=1-0.6\times 0.9

=1-0.54

=0.46

(ii) The probability that the target is hit by exactly one shot means either of one hit the target.

=Hit by Laura and missed by Philip or hit by Philip and missed by Laura

=0.4\times 0.9+0.1\times 0.6 [from equations (1),(4) and (3),(2)]

=0.36+0.06

=0.42

(iii)Given that the target was hit by exactly one shot, so, the given probability is 0.42 [from (ii) part]

No, the probability that the target was hit by Philip = probability of hitting the target by Philip and missing the target by Laura

=0.1\times 0.6 [from equations (3) and (2)]

=0.06

So, the probability of hitting the target by Philip

=\frac {0.06}{0.42}

=\frac {1}{7}

=0.143 (approx)

6 0
3 years ago
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