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telo118 [61]
3 years ago
12

Which line is parallel to the line that passes through the points (2, –5) and (–4, 1)? a. y=-x-5

Mathematics
2 answers:
Svetach [21]3 years ago
8 0
\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 2}}\quad ,&{{ -5}})\quad 
%   (c,d)
&({{ -4}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-(-5)}{-4-2}
\\\\\\
m\implies \cfrac{1+5}{-6}\implies \cfrac{6}{-6}\implies -1

now, a line parallel to one that has those two points, will also have the same slope, this line has a slope of -1

let's take a peek at \bf \begin{array}{llll}
y=&-x&-5\\
y=&-1x&-5\\
&\quad \uparrow &\quad \uparrow \\
&slope&y-intercept
\end{array}

notice the slope of that one... recall your y = mx+b, slope-intercept form
ratelena [41]3 years ago
6 0
The answer is D
the answer is D
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3 years ago
CCA has stated in 2017 that 36.5 % of its students are first generation college students.Suppose you sample 15 CCA students and
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Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - p) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 36.5% = 36.5/100 = 0.365

q = 1 - p = 1 - 0.365

q = 0.635

n = 15

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P(x = 1) = 15C1 × 0.365^1 × 0.635^(15 - 1) = 0.0095

P(x = 2) = 15C2 × 0.365^2 × 0.635^(15 - 2) = 0.038

P(x = 3) = 15C3 × 0.365^3 × 0.635^(15 - 3) = 0.095

P(x = 4) = 15C4 × 0.365^4 × 0.635^(15 - 4) = 0.16

P(x = 5) = 15C5 × 0.365^5 × 0.635^(15 - 5) = 0.21

k P(X = k)

0 0.0011

1 0.0095

2 0.038

3 0.095

4 0.16

5 0.21

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= √15 × 0.365 × 0.635

= 1.86

d) z = (x - mean)/standard deviation

x = 2

z = (2 - 5.475)/1.86 = - 1.87

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