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3 years ago

I need help on the question and I need to do it because I’m on a time schedule

Mathematics

1 answer:

VladimirAG [237]3 years ago

3 0

Answer:

126∏

Step-by-step explanation:

area = 2 * area of the circle + area of the rectangular surface

area = 2 * r² * ∏ + 2 * r * ∏ * h

area = (2 * r² + 2 * r * h) * ∏

area = (2 * 7² + 2 * 7 * 2) * ∏

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MATHS | Cousin needs help❤️ question bellow

Licemer1 [7]

Equation: y = 6 - 2x

Fill in the x numbers in the x which is next to -2 —> y = 6 - 2(0), y = 6 -2(1), y = 6 -2(3), and etc.

A) 0 —> 6
1 —> 4
2 —> 2
3 —> 0
4 —> -2
5 —> -4

B) Put a dot on y axis on number 6, then go down by 2 because your subtracting 2

C) 6 - 2x = 3
-6 -6
-2x = -3
-2/-2 -3/-2

X = 1.5

3 0

3 years ago

A rectangular package sent by a postal service can have a maximum combined length and girth (perimeter of a cross sectio) of 108

Morgarella [4.7K]

Answer:

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

Step-by-step explanation:

This is a optimization with restrictions problem.

The restriction is that the perimeter of the square cross section plus the length is equal to 108 inches (as we will maximize the volume, we wil use the maximum of length and cross section perimeter).

This restriction can be expressed as:

$4x+L=108$

being x: the side of the square of the cross section and L: length of the package.

The volume, that we want to maximize, is:

$V=x^2L$

If we express L in function of x using the restriction equation, we get:

$4x+L=108\\\\L=108-4x$

We replace L in the volume formula and we get

$V=x^2L=x^2*(108-4x)=-4x^3+108x^2$

To maximize the volume we derive and equal to 0

$\dfrac{dV}{dx}=-4*3x^2+108*2x=0\\\\\\-12x^2+216x=0\\\\-12x+216=0\\\\12x=216\\\\x=216/12=18$

We can replace x to calculate L:

$L=108-4x=108-4*18=108-72=36$

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

4 0

3 years ago

Read 2 more answers

Which of the following is known as a simpler form of Euclid's fifth postulate

Deffense [45]

Answer:

A. Playfair's axiom.

Step-by-step explanation:

In a plane, given a line and a point not on it, at most, one line parallel to the given line can be drawn through the point.

- this implies Euclid's fifth postulate.

8 0

2 years ago

Solve the given differential equation by undetermined coefficients. y'' 4y = 7 sin(2x)

kherson [118]

The solution to the given differential equation is yp=−14xcos(2x)

The characteristic equation for this differential equation is:

P(s)=s2+4

The roots of the characteristic equation are:

s=±2i

Therefore, the homogeneous solution is:

yh=c1sin(2x)+c2cos(2x)

Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:

yp=Axsin(2x)+Bxcos(2x)

If you take the second derivative of the equation above for yp , and then substitute that result, y′′p , along with equation for yp above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side, sin(2x) , you will find:

A=0

B=−14

Therefore,

yp=−14xcos(2x)

For more information about differential equation, visit

brainly.com/question/18760518

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2 years ago

What's 1÷0<br>If you got this right this means you're gifted!!

Olegator [25]

1 ÷ 0 is undefined. nothing can be divided by 0.

3 0

3 years ago

Read 2 more answers