So here, ABCD is being inscribed in a circle, so ABCD is a cyclic quadrilateral (as inscribed in a circle) also, there exists a property of cyclic quadrilateral, i.e, the sum of opposite angles of a cyclic quadrilateral is 180°, so we can just write the following equation using this :

${:\implies \quad \sf y^{\circ}+83^{\circ}=180^{\circ}}$

${:\implies \quad \sf y^{\circ}=180^{\circ}-83^{\circ}}$

${:\implies \quad \sf y^{\circ}=97^{\circ}}$

${:\implies \quad \boxed{\bf{y=97}}}$

6 0

1 year ago

A line goes through the point (6,–2) and has a slope of –3. What is the value of a if the point (a,7) lies on the line? A =

Sati [7]

Answer:

Step-by-step explanation:

Y = mx + b

slope(m) = 3/4

(3,7)...x = 3 and y = 7

now we sub...we r looking for b, the y int

7 = 3/4(3) + b

7 = 9/4 + b

7 - 9/4 = b

28/4 - 9/4 = b

19/4 = b

equation is : y = 3/4x + 19/4...lets put this in standard form

y = 3/4x + 19/4

-3/4x + y = 19/4...multiply by -4

3x - 4y = -19 <== standard form

if (x,5) is on the line

3x - 4y = -19.....sub in 5 for y

3x - 4(5) = -19

3x - 20 = -19

3x = -19 + 20

3x = 1

x = 1/3 <====so point a = (1/3,5)

4 0

3 years ago

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