Answer:
The lower confidence limit of the 95% confidence interval for the population proportion of Americans who were victims of identity theft is 0.0275.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
A 2003 survey showed that 14 out of 250 Americans surveyed had suffered some kind of identity theft in the past 12 months.
This means that 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:

The lower confidence limit of the 95% confidence interval for the population proportion of Americans who were victims of identity theft is 0.0275.
Answer:
24%
Step-by-step explanation:
Taxes
t = 55000 - 41800
t = 13200
% tax
p = 13200/55000 * 100
p = 24%
Answer:
9.99
Step-by-step explanation:
447,163 / 34,000 = 13.151
13.151 • 34,000 = 447,163
Your answer is going to be 13.151
-4x+7x-14
3x-14>-18
3x>-4
X>-4/3