Answer:
see below
Step-by-step explanation:
(ab)^n=a^n * b^n
We need to show that it is true for n=1
assuming that it is true for n = k;
(ab)^n=a^n * b^n
( ab) ^1 = a^1 * b^1
ab = a * b
ab = ab
Then we need to show that it is true for n = ( k+1)
or (ab)^(k+1)=a^( k+1) * b^( k+1)
Starting with
(ab)^k=a^k * b^k given
Multiply each side by ab
ab * (ab)^k= ab *a^k * b^k
( ab) ^ ( k+1) = a^ ( k+1) b^ (k+1)
Therefore, the rule is true for every natural number n
(A) The customer that owns a 3-kW system exports 120 kWh monthly to the grid will have the following bills for both companies:
For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be

For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be

(B) The customer that owns a 5-kW system exports 300 kWh monthly to the grid will have the following bills for both companies:
For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be

For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be
Answer:
Step-by-step explanation:
H
Two solutions were found :
u ≥ 2
u ≤ 0
Hello:
(3/4)x-3 = (1/2)x+2
(3x-12)/4 =(2x+8)/4
3x-12 = 2x+8
3x-2x = 12+8
x =20