Answer:
George must run the last half mile at a speed of 6 miles per hour in order to arrive at school just as school begins today
Step-by-step explanation:
Here, we are interested in calculating the number of hours George must walk to arrive at school the normal time he arrives given that his speed is different from what it used to be.
Let’s first start at looking at how many hours he take per day on a normal day, all things being equal.
Mathematically;
time = distance/speed
He walks 1 mile at 3 miles per hour.
Thus, the total amount of time he spend each normal day would be;
time = 1/3 hour or 20 minutes
Now, let’s look at his split journey today. What we know is that by adding the times taken for each side of the journey, he would arrive at the school the normal time he arrives given that he left home at the time he used to.
Let the unknown speed be x miles/hour
Mathematically;
We shall be using the formula for time by dividing the distance by the speed
1/3 = 1/2/(2) + 1/2/x
1/3 = 1/4 + 1/2x
1/2x = 1/3 - 1/4
1/2x = (4-3)/12
1/2x = 1/12
2x = 12
x = 12/2
x = 6 miles per hour
The solution is y < -1/5
In order to find the answer to this problem, follow the order of operations for solving equations/inequalities.
444 + 555y < 333 -----> Subtract 444 from both sides
555y < -111 -----> Divide both sides by 555
y < -1/5
Answer:
Kelsey is correct.
Step-by-step explanation:
One of the rules when solving an equation is that you need to isolate the variable, meaning that it just needs to be x by itself. To do that, you would need to start by subtracting 6. If you were to divide by 3 first, the answer would be twice what it should be.
Step-by-step explanation:
Here
5x+16+7x-3+6x+5 = 180(being sum of triangle)
or, 18x=180-18
or, x= 162/18
so, x = 9
now,
here,
<ACD = <ACB(diagonals of parallelogram bisect eachother)
or, <ACD = 7x-3
or, <ACD = 7×9-3
or, <ACD = 63-3
So, <ACD = 60°
Box-and-whisker plot
We are given the box-and-whisker plot that summarizes the magnitude of earthquakes.
The minimum value of the dataset is 2,5
The maximum value of the dataset is 8.5
The range is the difference:
Range = 8.5 - 2.5 = 6
Range = 6
