<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
20%
Step-by-step explanation:
14/70x100=20%
Answer: B. (-2, -1)
Step-by-step explanation:
(-2, -1) has a y-coordinate (-1) closer to 0 than the rest of the y-coordinates. And 0 would be turning point in this equation.
A=3,500×(1+0.0485÷4)^(4×11)
A=5,947.99
6000=3500(1+0.0485/4)^4t
Solve for t to know the time needed to reach 6000
Time=11.2
So the time needed is 11 years and 2 months
Answer:
The square root of 0.33 is the only irrational number.
Step-by-step explanation:
.25 NOT
sq rt. of .25 is .5
sq rt. of .33 is .574456....