Radius is half the circumference
c= 2(square root) pieA
Answer:
Step-by-step explanation:
Using the formula for the exponential decay that is , we have N=, and k=0.1374.
Thus, becomes
Taking log on both sides, we get
Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.
The relation 2+4+6+...+2n = n^2+n has to be proved.
If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2
Assume that the relation holds for any value of n.
2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)
= n^2 + n + 2n + 2
= n^2 + 2n + 1 + n + 1
= (n + 1)^2 + (n + 1)
This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.
<span>By mathematical induction the relation is true for any value of n.</span>
There are 8 tenths in the sum. .65+.24 is .89. tenths are the first digit to the right of the decimal. 80 and 8x10=80
Answer:
x = 4
Step-by-step explanation:
Cross multiply:
21*2 = 14(x - 1)
42 = 14x - 14
14x = 56
x = 4