Answer:
efg=hij*k=lmnop
Step-by-step explanation:
= r^-5 s^4t ^4
= s^4 t^4 / r^5
answer
answer is B, s^4 t^4 / r^5
It would be about 72.72727272727273 %
Opposite angles are supplementary, so you have
.. V +T = 180°
.. (15y -4) +(12y-5) = 180
.. 27y -9 = 180
.. y = 189/27 = 7
a) T = (12y -5)° = (12*7 -5)° = 79°
c) V = (15y -4)° = (17*7 -4)° = 101°
.. U +W = 180°
.. (14 +4x) +(6x -14) = 180
.. 10x = 180
.. x = 180/10 = 18
b) U = (14 +4x)° = (14 +4*18)° = 86°
d) W = (6x -14)° = (6*18 -14)° = 94°
Answer:
a. 0.00069
b. 0.063
c.0.00095
Step-by-step explanation:
a. Probability that exactly 5 men consider themselves professional baseball fans:-
Here, there's a 63/100 or 63% possiblity that five (5) men consider themselves fans and of course, a 37/100 possibility that the other 5 men consider themselves non fans. Each of these must be multiplied and then the result will be the probability that exactly five men consider themselves baseball fans:-
(63/100)^5 × (37/100)^5
= 0.09924 × 0.006934
= 0.000688
Therefore the probability that 5 consider themselves baseball fans is 0.00069
b. The probability that at least 6 are fans:-
In this case, each of the 6 men have some 63/100 or 63% possibility of being a fan.
We therefore multiply 63/100 by itself up to six times
i.e 63/100 × 63/100 × 63/100 × 63/100 × 63/100 × 63/100
or (63/100)^6
= 0.06252
The probability that at least 6 men consider themselves professional baseball fans is 0.063
c. Probability that less than four consider themselves baseball fans:-
In this scenario, it means that at least 7 men out of the ten do not consider themselves professional baseball fans. We then simply multiply 37/100 by itself up to seven times. It isn't too necessary what the remaining three are.
= (37/100)^7
= 0.0009493
Therefore the possibility that less than four men do not consider themselves baseball fans is 0.00095
