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Andrei [34K]
3 years ago
14

What is the Multiplication property of Equality

Mathematics
1 answer:
aev [14]3 years ago
5 0

Answer:

The Multiplication Property of Equality states that if you multiply both sides of an equation by the same number, the sides remain equal.

Step-by-step explanation:

hope this helps,

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How are we supposed to solve this question!?​
VashaNatasha [74]

Answer:

use pythagorean's theorem; x=6

Step-by-step explanation:

a^2 + b^2 = c^2

a=length; b(x)=height; c= hypotenuse (longest side)

8^2 + b^2 = 10^2

64 + b^2 = 100 (subtract 64 from each side)

b^2= 36

6 x 6 = 36 so b=6

x=6

6 0
3 years ago
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A population of 490 bacteria is introduced into a culture and grows in number according to the equation below, where t is measur
Lera25 [3.4K]

Answer:

Rate of growth of bacteria when t=2 is 3.09 bacteria/hour

Step-by-step explanation:

As equation is not given so considering the Equation of growth of bacteria as

P=490(1+\frac{4t}{50+t^{2}})

We have to find the rate at which population is growing. To do so differentiate above equation w.r.to 't'

\frac{dP}{dt}=\frac{d}{dt}490(1+\frac{4t}{50+t^{2}})\\\\\frac{dP}{dt}=490(\frac{d}{dt}(1)+\frac{d}{dt}(\frac{4t}{50+t^{2}}))\\\\\frac{dP}{dt}=490(0+\frac{4(50+t^{2})-(4t)(2t)}{(50+t^{2})^{2}})\\\\\frac{dP}{dt}=490(\frac{200+4t^{2}-8t^{2}}{(50+t^{2})^{2}})\\\\\frac{dP}{dt}=490(\frac{4(50-t^{2})}{(50+t^{2})^{2}})\\\\at\,\,t=2hours\\\\\frac{dP}{dt}=490(\frac{4(50-(2)^{2})}{(50+(2)^{2})^{2}})\\\\\\\frac{dP}{dt}=490(\frac{4(50-4)}{(50+4)^{2}})\\\\=3.09

Rate of growth of bacteria when t=2 is 3.09 bacteria/hour

8 0
3 years ago
Inequality to x2 < 64
Anarel [89]
              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
7 0
3 years ago
Help pleaseeeeeee❗️❗️❗️❗️
navik [9.2K]

Answer: B

Step-by-step explanation: Mr. Inderhees added 5 to each side of the equation for his first step to isolate the <em>x</em> term which in this case is 4x.

So when he added 5 to both sides of the equation, he got 20 = 4x.

4 0
3 years ago
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I’m not really sure what to choose..
SSSSS [86.1K]

Answer:

i think it would be SAS, sorry if I'm wrong!

Step-by-step explanation:

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3 years ago
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