The measure of the missing side is 3x^3 +2x - 7y + 9
<h3>Perimeter of a triangle</h3>
The perimeter of a triangle is equal to the sum of all the sides of the triangle. Mathematically;
P = s1 + s2 + s3
where;
s1 = s2 = -8x^3 + 2
P = -13x^3 + 2x - 7y + 3
Substitute the given parameters
-13x^3 + 2x - 7y + 3 = s3. + 2(-8x^3 + 2)
-13x^3 + 2x - 7y + 3 = s3 - 16x^3 -4
s3 = -13x^3 + 2x - 7y + 3 + 16x^3 + 6
s3 = 3x^3 +2x - 7y + 9
Hence the measure of the missing side is 3x^3 +2x - 7y + 9
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Answer:
117
Step-by-step explanation:
Given the expression
r³ - 2s ← substitute given values into the expression
= 5³ - 2(4)
= 125 - 8
= 117
Answer:
310339.1 in^3
Step-by-step explanation:
Volume=4/3*pi*r^3
Volume=4/3*pi*42^3
Volume=4/3*pi*74088
Volume=98784*pi
Volume=310339.0887
So the volume is about 310339.1 in^3
The answer would be 8x^4 + 16x^3y - 48x^2y^2
In order to find this, multiply 8x^2 by each term individually.
8x^2 * x^2 = 8x^4
8x^2 * 2xy = 16 x^3y
8x^2 * -6y^2 = -48x^2y^2
Now you can put them all in a row.
8x^4 + 16x^3y - 48x^2y^2
