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bogdanovich [222]
3 years ago
7

A graphic designer chose a base font size and represented it as 1 on the scale. he then listed some consecutive scale sizes. two

consecutive sizes were 5.832 and 10.4976.
what scale size came before 5.832 ?
Mathematics
1 answer:
garik1379 [7]3 years ago
4 0

Answer:

3.24

Step-by-step explanation:

You would use the two fonts given to find the scale factor.

So the scale factor would be 10.4976/5.832 = 1.8

So if the scale factor is 1.8 we can use that to find the font size just before that. To do this you would divide the font size by the scale factor.

So

5.832/1.8 = 3.24

The font size just before 5832 is 3.24.

Hope this helps, if there is an error in my work please correct me.

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Asa received scores of 72, 97, and 82 on her last three math tests. She needs a mean test score of 82 to qualify for the math te
Flauer [41]

Scores are {72, 97, 82, x} where x is the unknown fourth score

They add up to 72+97+82+x = x+251

Divide this sum over four because there are four scores we want to average out. We end up with (x+251)/4 = M where M is the mean. Asa wants the mean to be 82, so make M = 82.

We can replace M with 82 and solve for x like so

(x+251)/4 = M

(x+251)/4 = 82

x+251 = 4*82

x+251 = 328

x = 328-251

x = 77

Asa needs a score of 77 on the fourth test so that the mean of the four tests is 82. If she scores higher than 77 on the fourth test, then the mean will be larger than 82.

-----------------------------------

Depending on what your teacher is looking for, the first step is to establish your variable. So you would say "let x = fourth score". However, that seems too easy. So perhaps your teacher is looking for the equation (x+251)/4 = 82 or some variant of it.

5 0
3 years ago
Read 2 more answers
At 7:17AM this morning, it was 83˚F outside. What is 83˚F in Celsius? What is 83˚F in Kelvin?
Temka [501]

Answer: 28.33 Celsius and 301.483 Kelvin

83°F − 32) × 5/9 = 28.333°C

(83°F − 32) × 5/9 + 273.15 = 301.483K

4 0
3 years ago
Attached as picture. Please read fully
Troyanec [42]

a. The velocity t = v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. v60 = 7164

<h3>How to solve for the velocity</h3>

mdv/dt = ck - mg

dv/dt = ck/m - mg/m

= ck/m - g

dv = (\frac{ck}{Mo-Kt} -g)dv

Integrate the two sides of the equation to get

v -\frac{ck}{k} e_{n} (Mo- kt)-gt+c

v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. fuel accounts for 55% of the mass

So final mass after fuel is burned out is = 0.45

c=2500

g=9.8

t=60

v = -2500ln0.45 - 9.8 x 60

= 7752 - 588

= 7164

<h3>Complete question</h3>

A rocket, fired from rest at time t = 0, has an initial mass of m0 (including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m0 - kt. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity of the rocket will satisfy the equation where g is the acceleration due to gravity.

dv dt m =ck - mg

(a) Find v(t) keeping in mind that the mass m is a function of t.

v(t) =

m/sec

(b) Suppose that the fuel accounts for 55% of the initial mass of the rocket and that all of the fuel is consumed at 60 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g = 9.8 m/s² and c = 2500 m/s.]

v(60) =

m/sec [Round to nearest whole number]

Raed more on velocity here

brainly.com/question/25749514

#SPJ1

8 0
1 year ago
The sum of two numbers is 61. The larger number is 13 more than the smaller number. What are the numbers?
patriot [66]

Answer: 24 and 37

Step-by-step explanation:

Let the numbers be x and y . Also let us pick x as the larger number.

From the first statement :

x + y = 61 ............................ equation 1

From the second statement :

x = y + 13 ............................equation 2

Solving the resulting linear equations by substitution method, substitute x = y + 13 into equation 1, then

x + y = 61 becomes

y + 13 + y = 61

2y + 13 = 61

2y = 48

y = 24

Substitute y = 24 into equation 2 , then

x = y + 3 becomes

x = 24 + 13

x = 37

Therefore the numbers are 24 and 37

5 0
3 years ago
Which of the following data sets could most likely be normally distributed
mamaluj [8]
I’m not 100% but l’ll say go for D
7 0
2 years ago
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