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Lena [83]
3 years ago
15

Please help me with this math assignment

Mathematics
2 answers:
MrRissso [65]3 years ago
6 0

Answer:

1)80%

2)210%

3)65%

4)105%

Effectus [21]3 years ago
5 0

Answer:

80%

210%

65%

105%

Step-by-step explanation:

To solve for each of these equations, let's make them fractions first. The denominator will be 20 since that was the goal.

Elena did \frac{16}{20} pushps.

Jada did \frac{42}{20\\} pushups.

Lin did \frac{13}{20} pushups.

Andre did \frac{21}{20} pushups.

To convert this to percentages, let's multiply each by fraction by \frac{5}{5}. This will give us a denominator of 100. The denominator will represent the percentage.

Elena did \frac{16}{20} × \frac{5}{5} = \frac{80}{100} pushps. Elena did 80 percent of the pushups.

Jada did \frac{42}{20\\} × \frac{5}{5} = \frac{210}{100} pushups. Jada did 210 percent of the pushups.

Lin did \frac{13}{20} × \frac{5}{5} = \frac{65}{100} pushups. Lin did 65 percent of the pushups.

Andre did \frac{21}{20} × \frac{5}{5}  = \frac{105}{100} pushups. Andre did 105 percent of the pushups.

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Answer:

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Step-by-step explanation:

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3 years ago
What is the 7th term of the geometric sequence where a1 = -5 and a5 = -1,280?
8_murik_8 [283]
Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number.

Here we are give the initial term so we have to solve to solve for the common ratio...

a(5)=-1280 and a(1)=-5 so

-1280=-5r^(5-1)

-1280=-5r^4

256=r^4

256^(1/4)=r

4=r, so our sequence is:

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3 0
3 years ago
Michaela caught 3 fish, which weigh a total 19 1/2 pounds. One fish weighs 7 5/8 pounds and another weighs 5 3/4 pounds. How muc
algol13
Find a common denominator for 2,4,8. Which is 8. Change the fractions to new ones.

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3) 5 6/8= 46/8 one. Which is

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6 0
4 years ago
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What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
Pavel [41]

\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Explanation:</h2>

Using the quadratic formula:

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Learn more:</h2>

Quadratic functions: brainly.com/question/12164750

#LearnWithBrainly

8 0
3 years ago
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andrew11 [14]

Answer:32x+32

Step-by-step explanation:

Using the distributive property, you can simplify.

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