What is the company’s quick Ratio?

Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +

Veronika [31]

Answer:

Verified

$y(x) = \frac{3Ln(x) + 3}{x}$

$y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}$

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

$x^2y' +xy = 3$

- A general solution to the above ODE is also given as:

$y = \frac{3Ln(x) + C }{x}$

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

$y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x) }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}$

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

$-\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3$

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

$y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3$

- Therefore, the complete solution to the given ODE can be expressed as:

$y ( x ) = \frac{3Ln(x) + 3 }{x}$

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

$y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)$

- Therefore, the complete solution to the given ODE can be expressed as:

$y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}$

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6 0

3 years ago

What is the measure of an angle if it is 260 degrees less than six times its own complement?

poizon [28]

Answer:

40 degrees

Step-by-step explanation:

Complementary angles have a sum of 90.

y = 90 - x

The angle is 260 degrees less than six times its complement.

y = 6x - 260

90 - x = 6x - 260

350 - x = 6x

350 = 7x

50 = x

This is the measure of the complement.

y = 90 - x

y = 90 - 50

y = 40

This is the measure of the first angle.

7 0

3 years ago

A gourmet pizza café sells three sizes of pizzas. If you buy all three sizes, it costs $46.24. A medium pizza costs $15.75 and a

avanturin [10]

Answer:

Step-by-step explanation:

You need to subtract the prices of the medium and large from the total

Small = 46.24 - medium - large

17.50 + 15.75 = 33.75

S = 46.24 - 33.75

S = 12.99

8 0

3 years ago

Give an equation that goes through the line 3,-1 that is parallel to 6x-5

allochka39001 [22]

Lines that are parallel have the same slope, and the given line (y = 6x - 5) has a slope of 6; we are looking for a line with a slope of 6.
To form an equation for a line, you need to know the y-intercept (the point at which the line intersects the y-axis). The first step to finding the y-intercept is to plot the given point. After you've done that, count six units up (this is our slope) and one to the right; plot the point. Lastly, draw the line by connecting the points and see where the line intersects the y-axis.
My graph shows that the line intersects the y-axis at -17. All that's left now is to put our information together into an equation. I'm assuming the problem wants the equation in slope-intercept form; slope-intercept form is y = mx + b where m is the slope and b is the y-intercept, so it would look like this:
y = 6x -17

Hope this helps.

8 0

3 years ago

Read 2 more answers

Students set up the experiment shown in their Biology class. After 24 hours, students noticed gas had accumulated in one of the

Orlov [11]

Answer: Light caused the eludes plants to photosynthesize, releasing O2 gas

7 0

2 years ago