Answer:
-1, 2, 6
Step-by-step explanation:
We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).
Now, we have, 
⇒
⇒
⇒
⇒![(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0](https://tex.z-dn.net/?f=%28x-2%29%28x-6%29%5B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20-5x-2%7D%20-%5Cfrac%7B1%7D%7B4%7D%20%5D%3D0)
⇒ 
or, ![[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20-5x-2%7D%20-%5Cfrac%7B1%7D%7B4%7D%20%5D%3D0)
If, (x-2)(x-6) =0, then x=2 or x=6
If, , then 
and (x-6)(x+1) =0
Therefore, x=6 or -1
So the solutions for x are -1, 2 6. (Answer)
Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
This is middle school work woah
Answer:
10 + x/6
Step-by-step explanation:
The first two is worth 2,000 and the second is worth 200.
